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How to get REJECTED to display?

Posted on 1997-12-08
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Last Modified: 2010-04-02
This program suppose to allow the user to enter a social security nummber.
If the number matches on in the list it will display "ACCEPTED."  If it
doesn't match it will display "REJECTED".  To end the program the user
has to enter 000000000.

My problem with this program is when a social security number that does
not match is entered, the program displays nothing.  What could be the
problem.

Everything else works fine.



This is my code:

#include <stdio.h>
#include <stdlib.h>

void main()

{
long ssn[8] = {118456835,203658739,444545555,513587652,725468190,7967355113,861490579,921424023};
char buffer[25];
long l;
int x;

do
{
printf("\n\nEnter 000000000 to end program.");
printf("\nEnter Social Security Number ===>");
gets(buffer);

l=atol(buffer);

for(x=0; x<=7; x++)
      {

      if(ssn[x]==l)
            printf("\nACCEPTED");
       }

if(ssn[x]==000000000)
      printf("\nSearch Completed.");

else
//            if(l!=ssn[x])
            printf("\nREJECTED");
 
      }

while(l!=000000000);
}
0
Comment
Question by:lawrencej
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1 Comment
 
LVL 15

Accepted Solution

by:
Tommy Hui earned 150 total points
ID: 1256557
This section of your code will never be true:

if(ssn[x]==000000000)
printf("\nSearch Completed.");

Instead you should modify your code to be something like

int found = 0;
for(x=0; x<=7; x++)
{
  if(ssn[x]==l)
  {
    printf("\nACCEPTED");
    found = 1;
  }
}

if (found == 0)
  printf("\nRejected");


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