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  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 206
  • Last Modified:

How to get REJECTED to display?

This program suppose to allow the user to enter a social security nummber.
If the number matches on in the list it will display "ACCEPTED."  If it
doesn't match it will display "REJECTED".  To end the program the user
has to enter 000000000.

My problem with this program is when a social security number that does
not match is entered, the program displays nothing.  What could be the
problem.

Everything else works fine.



This is my code:

#include <stdio.h>
#include <stdlib.h>

void main()

{
long ssn[8] = {118456835,203658739,444545555,513587652,725468190,7967355113,861490579,921424023};
char buffer[25];
long l;
int x;

do
{
printf("\n\nEnter 000000000 to end program.");
printf("\nEnter Social Security Number ===>");
gets(buffer);

l=atol(buffer);

for(x=0; x<=7; x++)
      {

      if(ssn[x]==l)
            printf("\nACCEPTED");
       }

if(ssn[x]==000000000)
      printf("\nSearch Completed.");

else
//            if(l!=ssn[x])
            printf("\nREJECTED");
 
      }

while(l!=000000000);
}
0
lawrencej
Asked:
lawrencej
1 Solution
 
Tommy HuiEngineerCommented:
This section of your code will never be true:

if(ssn[x]==000000000)
printf("\nSearch Completed.");

Instead you should modify your code to be something like

int found = 0;
for(x=0; x<=7; x++)
{
  if(ssn[x]==l)
  {
    printf("\nACCEPTED");
    found = 1;
  }
}

if (found == 0)
  printf("\nRejected");


0

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