How to catch an Integer Overflow Exception?

I am trying to catch an integer overflow becuase my program adds up a bunch of large numbers with a potential for overflow.  I read through the SEH docs/examples and I wrote up a simple test program as follows:

  #include <windows.h>
  #include <fstream.h>

  int main()
  {
    unsigned long value = 4294967293;
    for( int i = 0; i < 5; i++ )
    {
      __try
      {
        value = value + 1;
      }
      __except( ( GetExceptionCode() ==
                  EXCEPTION_INT_OVERFLOW ) ?                         EXCEPTION_EXECUTE_HANDLER :
                EXCEPTION_CONTINUE_SEARCH )
      {
        cout << "overflow!" << endl;
      }
      cout << value << endl;
    }
    return( 0 );
  }

The problem is, I cannot catch the overflow of the variable "value"!  The output is as follows:

  4294967294
  4294967295
  0
  1
  2

If I changed the code to divide by zero somehow, and change
EXCEPTION_INT_OVERFLOW to EXCEPTION_INT_DIVIDE_BY_ZERO above, then the divide by zero exception is caught.  

Even if I switch to C++ exception handling (by replacing "__try" with "try" and "__except" with "catch( ... )") I still can't catch anything.  Any ideas what I am doing wrong?

EXCEPTION_INT_OVERFLOW is defined as "The result of an integer operation caused a carry out of the most significant bit of the result."  But that's all the documentation I can find on it.

Thanks!

Later,
Frank