Solved

testing for carriage return

Posted on 1997-12-14
5
387 Views
Last Modified: 2010-04-10
I would like to write a program that takes one command and sometimes one or two parameters.
I thought I would use an input statement like: cin>>Commandstr>>Paramonestr>>Paramtwostr;
I wanted to test Paramonestr for char 13 or '\r' to see if the user only entered a command (which is one possibility).
I also thought I could check the Commandstr var at the end for the carriage return char or newline char.  
How should I go about this, since my methods of testing for these values don't work?
Thanks for any help.
0
Comment
Question by:whatever080697
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
  • 2
5 Comments
 
LVL 11

Expert Comment

by:alexo
ID: 1176233
Why don't you check cin for eof?
0
 

Author Comment

by:whatever080697
ID: 1176234
Why test for EOF.  The user must enter one stream of input. Such as a command then a space then a name,space, company, user hits enter.  The user could also enter only a command depending on the command.  I need a way to take one char at a time then stop when a space is encountered, then save the char's taken into a string, then if more char's entered copy them into another string, until the user hits the enter key.

0
 

Accepted Solution

by:
jlilley earned 100 total points
ID: 1176235
This is overkill, but fairly general...


#include <iostream>
#include <string>
#include <list>
using namespace std;
void main()
{
   // Strings will be filled in as elements of words.
   // This inputs an arbitrary number of words on a single line.
   list<string> words;
   string tmp;
   char c;
   do {
      c = cin.get();
      if (c == ' ' || c == '\n') {
         // End of string
         words.push_back(tmp);
         tmp.resize(0);
      } else {
         tmp += c;
      }
   } while (c != '\n');

   cout << "The input strings were:" << endl;
   for (
      list<string>::iterator iter = words.begin();
      iter != words.end();
      ++iter
   ) {
      cout << *iter << endl;
   }
}

0
 

Author Comment

by:whatever080697
ID: 1176236
I think you got it, but what is list? A header file? I don't have it.  I've already basicly implemented your method, but does your method allow for more than one round of input. In other words, can I put your code in a loop and it'll still work?
0
 

Expert Comment

by:jlilley
ID: 1176237
The <list> is an STL template header file.  "Modern" C++ compilers have it.  It may be called "list.h" on some systems.  If you don't have STL, then just use an array of string instead.  If you don't have <string>, which is also a Standard C++ header, then use CString on MS-Windows.  Lacking that use a (gasp) array of char.  Good luck.
0

Featured Post

Free Tool: IP Lookup

Get more info about an IP address or domain name, such as organization, abuse contacts and geolocation.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Templates For Beginners Or How To Encourage The Compiler To Work For You Introduction This tutorial is targeted at the reader who is, perhaps, familiar with the basics of C++ but would prefer a little slower introduction to the more ad…
IntroductionThis article is the second in a three part article series on the Visual Studio 2008 Debugger.  It provides tips in setting and using breakpoints. If not familiar with this debugger, you can find a basic introduction in the EE article loc…
The goal of the tutorial is to teach the user how to use functions in C++. The video will cover how to define functions, how to call functions and how to create functions prototypes. Microsoft Visual C++ 2010 Express will be used as a text editor an…
The viewer will be introduced to the member functions push_back and pop_back of the vector class. The video will teach the difference between the two as well as how to use each one along with its functionality.

752 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question