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Microsoft Calendar Control

When using this in VB5 is there anyway to code the individual buttons of the Calendar. (ex. if I want it to highlight the button 15 days later.) If the user can choose the month on the first calendar and there is another calendar on the page how do you code it so it is the following month?

MrBump

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ASKER CERTIFIED SOLUTION

rantanen

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sachinkas

Hi Mr. Bump,
Please unlock the question. I have a perfect answer to the question..

Happy VBing
From Sachinkas

rantanen

It seems that I misunderstood the question. I thought you want to highlight _two_ buttons - the present day and a day eg. 15 days later. If you only want to highlight a day a certain offset from the date selected (and use two calendars side by side), you can call following sub

Public Sub HighLightDayOffset(nDays As Integer)
Dim NewDay As Integer
Dim LastDay As Integer
Const DAY_OFFSET_MAX = 30

If nDays > DAY_OFFSET_MAX Then Exit Sub

' Calculate number of days in current month
If IsDate(Calendar1.Month & "-31-" & Calendar1.Year) Then
LastDay = 31
ElseIf IsDate(Calendar1.Month & "-30-" & Calendar1.Year) Then
LastDay = 30
ElseIf IsDate(Calendar1.Month & "-29-" & Calendar1.Year) Then
LastDay = 29
Else
LastDay = 28
End If

If Calendar1.Day <= 0 Or Calendar1.Day > LastDay Then Exit Sub

NewDay = Calendar1.Day + nDays

If NewDay <= LastDay Then
Calendar1.Day = NewDay
Calendar2.Day = 0
Else
Calendar2.Value = 1
Calendar2.Day = NewDay - LastDay
Calendar1.Day = 0
End If
End Sub

This sub lets you add a certain offset to the selected date in the calendar1 and highlights the new date either in calendar1 or in calendar2.

sachinkas

Hi MrBump

Here is the solution for your bumpy question.
Create a form and draw the controls calendar1, calendar2 and a timer timer1 and a command button command1 for the next 15 days. And paste this code. Make the timer as 1 msec.

Private Function FindDays(mon As Integer, yea As Integer) As Integer
'Function to return the number of days of a month
Select Case mon
Case 1, 3, 5, 7, 8, 10, 12
FindDays = 31
Case 2
'Check for leap year
'Take the century
If yea Mod 100 = 0 Then
If yea Mod 400 = 0 Then
FindDays = 29
Else
FindDays = 28
End If
Else
If yea Mod 4 = 0 Then
FindDays = 29
Else
FindDays = 28
End If
End If
Case 4, 6, 9, 11
FindDays = 30

End Select

End Function

Private Sub Command1_Click()
Dim same As Integer

same = Calendar1.Day
Calendar1.Day = Calendar1.Day + 15
If Calendar1.Day = same Then 'See if it has gone to the next month
'if it has increase the
'Calendar1.FirstDay
totdays = FindDays(Calendar1.Month, Calendar1.Year) 'Function to find number of days in current month.
'Now check if the year is changed.
If Calendar1.Month = 12 Then
Calendar1.Month = 1
Calendar1.Year = Calendar1.Year + 1
Else
Calendar1.Month = Calendar1.Month + 1
End If
Calendar1.Day = 15 - (totdays - same)
End If
Calendar1.Refresh
End Sub

Private Sub Timer1_Timer()
Calendar2.Value = Calendar1.Value

End Sub

Happy VBing

From Sachin