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Bitwise And Operation

Posted on 1998-02-02
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Last Modified: 2012-06-21
I am confused on Bit Comparisons.  When doing a comparison of two bit values -> example

if ((nFlags & MK_LBUTTON)==MK_LBUTTON)
   cout .....

Assuming that MK_LBUTTON = 00000001 and nFlags was Unknown
If nFlags was equal to 01010101 , the if statement would be true?  or does nFlags have to 00000001?  Basically what I am asking is that when doing the comparision is it checking for only the one in the last bit or is it comparing the entire byte?  Can someone explain how this all works and what it might be useful for?

Thanks
DArrell
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Question by:larockd
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faster earned 20 total points
ID: 1180080
Only when nFlag is 00000001, it will be true.

You have to understand what is the outcome for a bit AND.  For example, 01010101 & 00000001 = 00000001 and 01010101 & 00001111 = 00000101.

If what you want is the opposite, the code should be:
if ((nFlags & MK_LBUTTON) != 0)
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by:faster
ID: 1180081
Sorry, I was so dumb when I gave the answer.

 if ((nFlags & MK_LBUTTON)==MK_LBUTTON)

As long as the last bit of nFlags is 1, it will be true.  It is the same as

 if ((nFlags & MK_LBUTTON)!=0) but the latter is more common.
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