Converting decimal to hexadecimal...

Does anyone know how to convert decimal to hexadecimal?
stepmaAsked:
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fontaineCommented:
Like this, it's OK!

private String itoHex(int i)
                          {
                          final char[] hex_array = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B',
                          'C', 'D', 'E', 'F'};
                          double radix = 16;

                          String s = "";

                              double A = (double)i;

                              while (A >= radix)
                              {
                              double B = A % radix;
                              A = Math.floor(A / radix);
                              s = hex_array[(int)(B)] + s;
                              }
                             
                              s = hex_array[(int)(A)] + s;
                          return s;
                          }
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fontaineCommented:
I thinck you could be interested by this page:

http://www.cut-the-knot.com/binary.html

If you do a "View|Page Source" with your browser, you can even access the Javascript code that the author of the page has used.
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fontaineCommented:
Huum, you should read the Web page again!!!
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stepmaAuthor Commented:
I am not too sure if I understand it, plus they are using Javascript stuff like Math.floor()
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fontaineCommented:

> they are using Javascript stuff like Math.floor()

There is exactly the same in Java!

Class Math: public static native double floor(double a)


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stepmaAuthor Commented:
I've tried to do everything that he does, and mine does not work correctly.  

private String itoHex(int i)
      {
            final char[] hex_array = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B',
                        'C', 'D', 'E', 'F'};
            double radix = 16;
            
            String s = "";

                double A = (double)i;

                while (A >= radix)
                {
                    double B = A % radix;
                    A = Math.floor(A / radix);
                    s += hex_array[(int)(B+1)];
                }
   
               s += hex_array[(int)(A+1)];
            return s;
      }
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stepmaAuthor Commented:
Thanks, it works, I was close, but I had the  + 1 happening when I shouldn't have.
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fontaineCommented:
Yes, and also:

s += hex_array[(int)(B)];

is not the same as: s = hex_array[(int)(B)] + s; because you use Strings:

if A = "a" and B = "b":

A += B => "ab"
A =B+A => "ba"
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