Go Premium for a chance to win a PS4. Enter to Win

x
?
Solved

Positionin a popup menu

Posted on 1998-02-20
3
Medium Priority
?
261 Views
Last Modified: 2010-04-16
I am creating a Swing-based application. One of the frames in that application displays a tree. When user clicks with a right mouse button on a tree node a popup menu apperas. My question is related to the positioning of that menu.

Does anyone has a code or an algorithm which allows to position a popup menu in such a way that the menu is always completely visible (that is it is not completetly or partially hidden by the edge of the screen or edge of the parent frame. That means it has to be positioned based on the cursor location as well as various edges.  I am looking for a behavior similar to that of popup menus in Microsoft Windows Explorer in 95 and NT.

I am not looking for a general description of the approach I shoud take but rather for an exact algorithm or even better a code which implements such behavior.
0
Comment
Question by:msmolyak
  • 2
3 Comments
 
LVL 3

Accepted Solution

by:
gwalters earned 600 total points
ID: 1233171
Dimension sz=menu.size();
Dimension scrsz=Toolkit.getDefaultToolkit.getScreenSize();
Point loc=CURSOR_LOCATION;
menu.move(Math.max(loc.x,scrsz.width-sz.width),Math.max(loc.y,scrsz.height-sz.height));




I put a holder for CURSOR_LOCATION because, without your code, I didn't know how you would get that.

Basically, the x,y coordinate of the click is the preferred location.  Move it up or to the left if putting it there would cause it to be offscreen.
0
 
LVL 3

Expert Comment

by:gwalters
ID: 1233172
Oops, those should be Math.min, not Math.max!

sorry.
0
 
LVL 5

Author Comment

by:msmolyak
ID: 1233173
I slightly modified you logic to come up with

// Position the menu on the screen
Dimension sz=menu.size();
Dimension scrsz=Toolkit.getDefaultToolkit().getScreenSize();
if (scrsz.width - (parentFrame.getLocationOnScreen().x + x) < sz.width)
{
    // If the cursor is close to the right edge of the screen,
    // position the menu to the left of the cursor
    x = (parentFrame.getLocationOnScreen().x + x) - sz.width;
}
else
{
    // Position the menu to the right of the cursor
    x = parentFrame.getLocationOnScreen().x + x + 10;
}
y = Math.min(parentFrame.getLocationOnScreen().y + y + 25,
             scrsz.height-sz.height);

this.menu.setLocation(x,y);

Thanks for your help.
0

Featured Post

VIDEO: THE CONCERTO CLOUD FOR HEALTHCARE

Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

By the end of 1980s, object oriented programming using languages like C++, Simula69 and ObjectPascal gained momentum. It looked like programmers finally found the perfect language. C++ successfully combined the object oriented principles of Simula w…
Basic understanding on "OO- Object Orientation" is needed for designing a logical solution to solve a problem. Basic OOAD is a prerequisite for a coder to ensure that they follow the basic design of OO. This would help developers to understand the b…
This theoretical tutorial explains exceptions, reasons for exceptions, different categories of exception and exception hierarchy.
How to fix incompatible JVM issue while installing Eclipse While installing Eclipse in windows, got one error like above and unable to proceed with the installation. This video describes how to successfully install Eclipse. How to solve incompa…
Suggested Courses

916 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question