Why doesn't return value?

I have a problem here. I have written 2 programs - one is to read input data from a text file using StreamTokenizer and pass the input to the other program which is the data structure. Somehow I could not get my data structure to print out the input. Could you please check whether I did my programming correctly?

This is my first program called Parser.java in which I wrote this program based on this grammar:
      parse_file -> parse_item  parse_file
      parse_item -> pItem | lItem | rItem
      pItem -> POINTS  object  attlist  pbody
      object -> STRING

I'm giving you part of my program here:
      
Vector parse_file() throws IOException, ParserException {
            Vector file = new Vector();

            parse_item(file);
            int token = stok.nextToken();
            if (!NextStringToken("end")) {
                  if (token == stok.TT_WORD) {      
                        return (this.parse_file());
                  }
            }
            return file;
      }

      SpatialCategory parse_item(Vector file) throws IOException, ParserException {
            if (NextStringToken("POINTS")) {
                  return (pItem(file));
            }
            return (pItem(file));
      }

      PointCategory pItem(Vector file) throws IOException, ParserException {
            PointCategory sc = new PointCategory();
            file.addElement(sc);

            this.MatchString("POINTS");
            object(sc);
            attlist(sc);
            pbody(sc);

            return sc;
      }
      
      SpatialCategory object(SpatialCategory sc) throws IOException, ParserException {
            int tok;
            if ((tok = stok.nextToken()) != stok.TT_WORD) {
                  throw new ParserException("Object is not word!");
            }
            else {
                  System.out.println("Object: " + stok.sval);
                  sc.name = stok.sval;
            }
            return sc;
      }

My input file:(for this part of program)
      POINTS
      postoffice
When I ran this program, it could read the value postoffice
and printed it out.

This is my data structure program - SpatialCategory.java
public class SpatialCategory extends Applet {
      String name;
      Vector atts = new Vector();

      public void paint(Graphics screen) {
            System.out.println(" " + name);
      }
}

class PointCategory extends SpatialCategory {
      Vector pIndividuals = new Vector();
                  
}

When I ran this program, it will printed out the value name as null in which it should be postoffice.

Can you please help me.
suhaniAsked:
Who is Participating?

[Webinar] Streamline your web hosting managementRegister Today

x
 
imladrisConnect With a Mentor Commented:
The simplest solution, I think, is to combine them into a single program. Parser becomes part of the initialization of the whole program. The data it has read in, is then available to the program in some convenient form.

0
 
imladrisCommented:
I'm not quite clear on why you would expect different behaviour.
SpatialCategory is a Java program. It is independent of (i.e.
knows nothing of) any other Java, C, C++ or any other code or
program in the system.
The variable name is declared as a String, but nothing is ever
assigned to it. Therefore its value is null.

Did I miss something? Was there something not posted or misposted?

0
 
suhaniAuthor Commented:
Then how do I connect between these two programs?
0
Never miss a deadline with monday.com

The revolutionary project management tool is here!   Plan visually with a single glance and make sure your projects get done.

 
suhaniAuthor Commented:
But when I combined these two programs, it would not run. Could you please tell me why?
0
 
imladrisCommented:
I'd be happy to try, but you'll have to be more specific. There are millions of things that could go wrong. Is the compiler complaining? Are you getting an exception? Is it producing the wrong results? Include some relevant code.

0
 
suhaniAuthor Commented:
It's ok now. Thank you.
0
All Courses

From novice to tech pro — start learning today.