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Copy a file?

How do I copy a autoexec.bat to the current directly (i mean the dir that has my app in it).   I would like this to be a VERY simple process, so please help me and explain everything!

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1 Solution
Please tell us what OS and compiler you are using. (win95? dos?)
Would you like to write a program to do this, or just use a DOS command?
Also, if you want a full program, you will need to increase the amount of points.

In a program under windows95 and NT, you can use the CopyFile() function:
  CopyFile("c:\\autoexec.bat", ".\\autoexec.bat", FALSE);

If you want to do it in a batch file (mind the dot!):
   copy c:\autoexec.bat .

stevenc317Author Commented:
I am using Broland Builder v3.0 on Windows 95..  I just need a line or two of codes.
Use the CopyFile() function as I suggested above.

Documentation says:

The CopyFile function copies an existing file to a new file.
BOOL CopyFile(
    LPCTSTR lpExistingFileName,      // pointer to name of an existing file
    LPCTSTR lpNewFileName,      // pointer to filename to copy to
    BOOL bFailIfExists             // flag for operation if file exists
lpExistingFileName - Points to a null-terminated string that specifies the name of an existing file.
lpNewFileName - Points to a null-terminated string that specifies the name of the new file.
bFailIfExists - Specifies how this operation is to proceed if a file of the same name as that specified by lpNewFileName already exists. If this parameter is TRUE and the new file already exists, the function fails. If this parameter is FALSE and the new file already exists, the function overwrites the existing file and succeeds.
Return Values:
If the function succeeds, the return value is TRUE.
If the function fails, the return value is FALSE. To get extended error information, call GetLastError.

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