Byte Array to Integer

I have a byte[] array of size 4 which I want to convert into a 4-byte int or Integer. What method should I use to do this?

I have tried:
String key = new String(bArray, 0, 3);
int result = Integer.valueOf(key).intValue();

which does not seem to work.

Any help would be appreciated.
iwtAsked:
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peter_vcCommented:
I think you can just cast it to an Integer:

String key = new String(bArray,0,3);
int result = int(key);

I don't have my Java stuff installed on this machine so I can't test it.

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iwtAuthor Commented:
No answer needed; I found a solution using the code from RandomAccessFile.java's WriteInt() and reversing it, which bypasses the need for a String.

For others' use, I've posted it below:

int result = ((bArray[0] << 24) | (bArray[1] << 16) + (bArray[2] << 8) + bArray[3]);

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anguslaiCommented:
Convert a byte array of 4 into 32 bits integer :

Assume :
     byte array named byteArray
     byte[0] contained the left most  8 bits (bit 25 to bit 32);
     
then use the following code to convert byteArray to int:
    int A = byteArray[0]<<24 | byteArray[1]<<16 | byteArray[2]<<8 | byteArray[3];

Note: the left most bit in primitive type int is a sign bit. Therefore, don't forget to treat the left most bit in byte[0] as sign bit.
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