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Byte Array to Integer
Posted on 1998-04-12
I have a byte[] array of size 4 which I want to convert into a 4-byte int or Integer. What method should I use to do this?
I have tried:
String key = new String(bArray, 0, 3);
int result = Integer.valueOf(key).intVa
which does not seem to work.
Any help would be appreciated.
I have tried:
String key = new String(bArray, 0, 3);
int result = Integer.valueOf(key).intVa
which does not seem to work.
Any help would be appreciated.
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3 Comments
I think you can just cast it to an Integer:
String key = new String(bArray,0,3);
int result = int(key);
I don't have my Java stuff installed on this machine so I can't test it.
String key = new String(bArray,0,3);
int result = int(key);
I don't have my Java stuff installed on this machine so I can't test it.
No answer needed; I found a solution using the code from RandomAccessFile.java's WriteInt() and reversing it, which bypasses the need for a String.
For others' use, I've posted it below:
int result = ((bArray[0] << 24) | (bArray[1] << 16) + (bArray[2] << 8) + bArray[3]);
For others' use, I've posted it below:
int result = ((bArray[0] << 24) | (bArray[1] << 16) + (bArray[2] << 8) + bArray[3]);
Convert a byte array of 4 into 32 bits integer :
Assume :
byte array named byteArray
byte[0] contained the left most 8 bits (bit 25 to bit 32);
then use the following code to convert byteArray to int:
int A = byteArray[0]<<24 | byteArray[1]<<16 | byteArray[2]<<8 | byteArray[3];
Note: the left most bit in primitive type int is a sign bit. Therefore, don't forget to treat the left most bit in byte[0] as sign bit.
Assume :
byte array named byteArray
byte[0] contained the left most 8 bits (bit 25 to bit 32);
then use the following code to convert byteArray to int:
int A = byteArray[0]<<24 | byteArray[1]<<16 | byteArray[2]<<8 | byteArray[3];
Note: the left most bit in primitive type int is a sign bit. Therefore, don't forget to treat the left most bit in byte[0] as sign bit.
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