MAPI Attachment Access

I am trying to access information on a file attachment in Exchange using MAPI in VB 5.0.  This is explained quite well in the MS Knowledgebase but the code examples I find there do not work for me.  All the other MAPI examples seem to work fine when when I try to check any Attachment property I get a "run time error 438 - Object doesn't support this property or method" error.

I have tried it both using the MAPI on form controls and the  Set objSession = CreateObject("mapi.session") commands.

My code is:
  MapiSess.Action = 1
  If Err <> 0 Then
      MsgBox "Logon Failure: " + Error$
  Else
      MapiMess.SessionID = MapiSess.SessionID
  End If
  On Error GoTo 0
  MsgBox MapiMess(1).AttachmentCount 'This failes
  MapiMess(1).AttachmentIndex = 1 'This fails
  MsgBox MapiMess(1).AttachmentPathName 'This fails

I have also tried fetching the message first with no improvement.  My guess is that I'm not including some necessary reference or component but I can't figure out which.

I am referencing:
Microsoft MAPI Controls 5.0 (sp2)
Microsoft Active Messaging 1.1 object library

My conponents are:
Microsoft MAPI Controls 5.0 (sp2)

Any help is greatly appreciated.

Ken
kfenskeAsked:
Who is Participating?
 
bin_huwairibConnect With a Mentor Commented:
kfenske,
To access a file attachment using MAPI control, you must create a message set for all messages in the inbox (after establishing MAPI Session) by using Fetch method, and then you can access each message in that set with MsgIndex property and finally you can use AttachmentIndex property to access selected message attachment.

Example:
MapiSess.Action = 1
If Err <> 0 Then
 MsgBox "Logon Failure: " + Error$
Else
 MapiMess.SessionID = MapiSess.SessionID
 MapiMess.FetchUnreadOnly = False
 MapiMess.Fetch
 For I = 0 To MapiMess.MsgCount - 1
  MapiMess.MsgIndex = I
  MsgBox "From : " + MapiMess.MsgOrigDisplayName + vbCrLf + _
   "Attachment Count : " + Trim(MapiMess.AttachmentCount) + vbCrLf + _
   "Attachment Path : " + Trim(MapiMess.AttachmentPathName)
 Next
End If



0
 
kfenskeAuthor Commented:
Excellent answer, this cleared it all up.

Ken
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