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How can I have two buttons behave as one

Posted on 1998-06-06
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Last Modified: 2010-04-06
I am using the buttons from Magikit.  So I am using 2 buttons with a picture between them.  This in fact looks like it is one button. It looks very nice except for the fact that this buttons also have the property of changing appearance when the cursor is on top of them. So if I am on top of the first button, I would like the second's button' appearance to change as well since they are meant to look like one button. How can I make sure they are in sync that way ?
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Question by:skylinka
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1 Comment
 
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Accepted Solution

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Matvey earned 100 total points
ID: 1351228
Hi

Sorry, don't know what is Magikit, so if it's something cool let me know...

The code below works for TSpeedButton, but I'm sure it's adjustable for your buttons. Your buttons might also have events for mouseenter and mouseleave, but here I create them by myself so the code is a bit long.

PS if you want to see even more cool button behavior, post your email and I'll send you a component I worte...

unit Unit1;

interface

uses
  Windows, Messages, SysUtils, Classes, Graphics, Controls, Forms, Dialogs,
  StdCtrls, Buttons;

type
  TNewSpeedButton = class(TspeedButton)
  private
    FOnMouseEnter: TNotifyEvent;
    FOnMouseLeave: TNotifyEvent;
  Protected
    procedure CMMouseEnter(var Message: TMessage); message CM_MOUSEENTER;
    procedure CMMouseLeave(var Message: TMessage); message CM_MOUSELEAVE;
  Published
    Property OnMouseEnter: TNotifyEvent read FOnMouseEnter write FOnMouseEnter;
    Property OnMouseLeave: TNotifyEvent read FOnMouseLeave write FOnMouseLeave;
  end;

  TForm2 = class(TForm)
    SpeedButton1: TSpeedButton;
    procedure FormCreate(Sender: TObject);

    procedure btn1MouseEnter(Sender: TObject);
    procedure btn1MouseLeave(Sender: TObject);
    procedure btn2MouseEnter(Sender: TObject);
    procedure btn2MouseLeave(Sender: TObject);
  private
    { Private declarations }
  public
    btn1, btn2 : TNewSpeedButton;
  end;

var
  Form2: TForm2;

implementation

{$R *.DFM}

procedure TNewSpeedButton.CMMouseEnter(var Message: TMessage);
Begin
  Inherited;
  if Assigned(FOnMouseEnter) then FOnMouseEnter(Self);
end;

procedure TNewSpeedButton.CMMouseLeave(var Message: TMessage);
Begin
  Inherited;
  if Assigned(FOnMouseLeave) then FOnMouseLeave(Self);
end;

procedure TForm2.btn1MouseEnter(Sender: TObject);
Begin
  Btn2.OnMouseEnter := nil;
 btn2.Perform(CM_MOUSEENTER, 0, 0);
  Btn2.OnMouseEnter := btn2MouseEnter;
end;

procedure TForm2.btn1MouseLeave(Sender: TObject);
Begin
  Btn2.OnMouseLeave := nil;
 btn2.Perform(CM_MOUSELEAVE, 0, 0);
  Btn2.OnMouseLeave := btn2MouseLeave;
end;

procedure TForm2.btn2MouseEnter(Sender: TObject);
Begin
  Btn1.OnMouseEnter := nil;
 btn1.Perform(CM_MOUSEENTER, 0, 0);
  Btn1.OnMouseEnter := btn1MouseEnter;
end;

procedure TForm2.btn2MouseLeave(Sender: TObject);
Begin
  Btn1.OnMouseLeave := nil;
 btn1.Perform(CM_MOUSELEAVE, 0, 0);
  Btn1.OnMouseLeave := btn1MouseLeave;
end;

procedure TForm2.FormCreate(Sender: TObject);
begin
  Btn1 := TNewSpeedButton.Create(Self);
  Btn2 := TNewSpeedButton.Create(Self);
  Btn1.Parent := Self;
  Btn2.Parent := Self;

  btn1.SetBounds(20, 20, 20, 20);
  btn2.SetBounds(40, 20, 20, 20);
  btn1.Caption := 'A';
  btn2.Caption := 'B';
  btn1.Flat := True;
  btn2.Flat := True;

  Btn1.OnMouseEnter := btn1MouseEnter;
  Btn2.OnMouseEnter := btn2MouseEnter;
  Btn1.OnMouseLeave := btn1MouseLeave;
  Btn2.OnMouseLeave := btn2MouseLeave;
end;

end.


(A code of a simple Delphi unit...)
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