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Load an image into a bitmap

zeekial
zeekial asked
on
Medium Priority
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Last Modified: 2013-12-03
I have some raw 8-bit grayscale data that I want to load into a bitmap.  Can anyone give me directions on how to load this data and display it in a CFormView.  I'm using VC5.0 and MFC. Thanx

zeekial@yahoo.com
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Commented:
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Commented:
Allocate memory by any function or C++ new operator. Read file into this buffer. Call CreateDIBitmap to create DIB. Then you can either use StretchDIBits, SetDIBitsToDevice to draw DIB or to convert it to DDB and then use BitBlt or StretchBlt

Author

Commented:
Here's some code to show you where I stand:

int fh;
char buffer[60000];
unsigned int nbytes = 60000;

fh = open("imagefile",O_RDONLY)
read(fh, buffer, nbytes);

now all my data is in character buffer "buffer".  How do I put this data into a bitmap and BitBlt it?  

Commented:
Is "imagefile" an actual image of a particular type, or is it simply a collection of bits?

How do you know the format (number of rows and columns) in imagefile?

Author

Commented:
"imagefile" is raw data of a 300X200 grayscale image I saved from another program.

Commented:
IF THIS IS A GRAYSCALE IMAGE IT IS ASSUMED EACH BYTE in image data is between 0 and 255. So you can create grayscale palette and create DIB from you image data so that eacch byte would be corresponding index in the palette.
Commented:
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Commented:
I haven't done this in so long I forgot something.  The BITMAPINFOHEADER  and BITMAPINFO and color table are ussually created as one structure.  Like
BITMAPINFO *BMIPtr = (BITMAPINFO *) new char[sizeof BITMAPINFOHEADER) + sizeof(RGBQUAD)*256];

Then you wild fill in the BITMAPINFOHEADER part as I showed above and fill in the color table appropriately (depending on your color format etc.)

We can discuss some of these things, but you might want to look into the docs on
BITMAPINFO BITMAPINFOHEADER and CreateDIBitMap() first.
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