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Get the position of a word in a line written on a canvas?

Posted on 1998-06-08
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Last Modified: 2010-04-04
I have a function which writes a line onto a canvas. This line should fit the entire width of my canvas so that I call SetTextJustification API function which "distributes the specified extra space evenly among the specified "number of spaces".

But how can I retrieve the X, Y position of the word - say - 'sample' on my canvas ?

Any help is greatly appreciated.

Greetings from Hungary,
Levente
slv@mcse.hu

----------------------------------------------------------------------------
-----------------------
var Text  : PChar;
    TextW : integer;   { TextWidth }
begin
   Text:=StrAlloc(128);
   Text:='This is a sample text for SetTextJustification.';

   { TextWidth}
   TextW:=LoWord( GetTextExtent(Image1.Canvas.Handle, Text, StrLen(Text)));

   SetTextJustification( Image1.Canvas.Handle, Image1.Width - TextW, 6 );
                       
   TextOut(Image1.Canvas.Handle, 0, 0, Text, StrLen(Text) );
   StrDispose(Text);
end;
----------------------------------------------------------------------------
----------------------------
0
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Question by:Levente
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3 Comments
 

Author Comment

by:Levente
ID: 1351562
Edited text of question
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LVL 5

Accepted Solution

by:
inter earned 200 total points
ID: 1351563
Hi,
The following may solve the problem: Assuming the text contains the string above and all the other values are computed

var
  SPos : integer; //at the end this will be the X position of sample
  TStr   : PChar;
  ...
begin
  ....
  TStr := AllocStr(128);
  // Find the character position of 'sample', here I do not understand why you use
  // null terminated strings and API calls. The width of the strings is given simply
  // by Image1.Canvas.TextWidth(Text); Any way
  SPos := StrLen(Text) - StrLen(StrPos(Text, 'sample'));
  // copy string upto sample
  StrLCopy(TStr, Text, SPos);
  // measure the string, this gives unadjusted X to sample
  SPos := Image1.Canvas.TextWidth(StrPas(SPos));
  // now add the extra spacing introduced by (Image1.Width - TextW)/ 6 (LOOK ABOVE)
  // one routine should count the number of SPACES for X pos be correct
  // Getbreakcount count the number of specified characters in you string
  SPos := SPos + ((Image1.Width - TextW) div 6)*GetBreakCount(TStr, ' ');
  // OK NOW YOU HAVE X POS OF SAMPLE IN SPOS
  StrDispose(TStr);
.
end;

function GetBreakCount( S : PChar; C:char):integer;
begin
   Result := 0;
  while S^ <> #0 do
  begin
      if S^ = C then Inc(Result);
      Inc(S);
  end;
end;

Note that your problem is ambigious. for example what if we do if the string contains the same word twice. So in most cases the user should know what he is doing

May this helps
Regards, Igor
0
 

Author Comment

by:Levente
ID: 1351564
Thanx for your answer. It exactly does what I needed.
(I used API calls because they're significantly faster (>50 %)
than Delphi functions - accodring to MY measurements.)

Levente
0

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