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date validation

Posted on 1998-06-09
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Last Modified: 2010-05-03
dear sir,

l'm doing the date validation programming, for example, if todays is april 98, then how do l know that this month is got 30,31 or just 28 days ?
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Question by:e_aks
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Accepted Solution

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SergeD earned 30 total points
ID: 1462869
Hi,

there is no special function which returns the number of days in the month. But you can easily make a loop until the date pass to the next month.

Private Function NbDays(ByVal iMonth As Integer, _
                                     ByVal iYear As Integer) As Integer
Dim i As Integer
Dim MyDate As Date

MyDate = CDate("28/" & Format(iMonth) & "/" & Format(iYear))

' Loop for the 29, 30 and 31
For i = 1 To 4
    If Val(Format(MyDate, "mm")) > iMonth Then
        NbDays = 26 + i
        Exit Function
    End If
    MyDate = MyDate + 1
Next i

NbDays = 31

End Function

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Expert Comment

by:mmahdi
ID: 1462870
e_aks,

You can use the following function as a General Procedure:

Public Function LastOfMonth(Optional vdatBase As Variant, Optional viOffset As Variant) As Date

       Dim datBase As Date
       Dim iOffset As Integer

              If Not IsMissing(vdatBase) Then
                      datBase = CDate(vdatBase)
              Else
                      datBase = Date
              End If


              If Not IsMissing(viOffset) Then
                      iOffset = CInt(viOffset)
              Else
                      iOffset = 0
              End If

       LastOfMonth = DateSerial(Year(datBase), Month(datBase) + iOffset + 1, 0)
End Function

to get the last day of each month try:

msgbox LastOfMonth(now) 'will return "30 June 1998"

Regards
mmahdi
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