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open file Error

When i do the following , VB gave me a path not found message (highlighting line 2) Why ?
open "c:\windows\temp\file1.text" for Input as #1
open "c:\windows\temp\file2.text" for Input as #2
Data = "Myname"
Put #1 Data
1 Solution

  What it really means is the file "c:\windows\temp\file2.text" is not existed! Open statement will create file for non-existed file path *only* for Append, Binary, Output, or Random modes.

  Besides, it is better to use the FreeFile function to obtain the next available file number.

eg.  Dim iFile as Integer
     iFile = FreeFile
     Open "C:\temp\test.txt" for output As #iFile

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