Solved

`Passing an array of a structure as argument

Posted on 1998-06-17
15
195 Views
Last Modified: 2010-04-01
I would like know how to pass by reference an array of a structure as argument to a function and how I can use this array in the function.  Could somebody tell me how to do this please ?  Thanks.

My code looks like this:

struct TEST
{
  int a;
  int b;
  int c;
  bool d;
}

void main()
{
  TEST TstArray[10];
  F1(???????);
]

Void F1(?????)
{
   //Here , how could I use the array ?
}
0
Comment
Question by:tam031198
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 5
  • 4
  • 4
  • +1
15 Comments
 
LVL 3

Accepted Solution

by:
Norbert earned 50 total points
ID: 1166047
Answer is coming
0
 
LVL 3

Expert Comment

by:Norbert
ID: 1166048
void F1(TEST& *Array, int Size)
{
    for(int i=0;i<Size;i++)
    {
       Array[i].a=Something
.
    }
}
0
 
LVL 22

Expert Comment

by:nietod
ID: 1166049
Small problem there.  Typo?  You want.

void F1(TEST *Array, int Size)
     {
         for(int i=0;i<Size;i++)
         {
            Array[i].a=Something
     .
         }
     }

or, I beleive this works, but I never use it, so I'm not sure.

void F1(TEST Array[], int Size)
     {
         for(int i=0;i<Size;i++)
         {
            Array[i].a=Something
     .
         }
     }





0
What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

 
LVL 11

Expert Comment

by:alexo
ID: 1166050
Nietod's version is the correct one.

>> I beleive this works, but I never use it, so I'm not sure.
It works and also conveys more information to the reader.

And the call will be:

F1(TstArray, 10);
0
 
LVL 22

Expert Comment

by:nietod
ID: 1166051
>>  conveys more information to the reader

What information? Just, the fact that it is an array and not an pointer to 1 item.  Or is there something else?  
0
 

Author Comment

by:tam031198
ID: 1166052
Here is my code:

#include <stdio.h>
struct TEST
{
      int a;
      int b;
      int c;
      bool d;
};

void main()
{
      void F1(TEST);  

        TEST TstArray[10];
      F1(TstArray);
        printf("Element 0 = %d\nElement 1 = %d\n",TstArray[0].a,TstArray[1].a);
}    

void F1(TEST *TstArray)
{
      TstArray[0].a = 1;
      TstArray[1].a = 10;
}

and I got this error while compiling:
error C2664: 'F1' : cannot convert parameter 1 from 'struct TEST [10]' to 'struct TEST'.

Could you tell me why please ?
0
 
LVL 22

Expert Comment

by:nietod
ID: 1166053
You have declared two versions (overloads) of F1.  One was supposed to be a forward reference for the second, but it doesn't have the same parameters. It takes a signel TEST argument.  The other takes a pointer to an array of TEST  arguments.

Change the

void main()
     {
           void F1(TEST);  

       TEST TstArray[10];
           F1(TstArray);
       printf("Element 0 = %d\nElement 1 = %d\n",TstArray[0].a,TstArray[1].a);
     }    

to

void main()
     {
           void F1(TEST *);  

       TEST TstArray[10];
           F1(TstArray);
       printf("Element 0 = %d\nElement 1 = %d\n",TstArray[0].a,TstArray[1].a);
     }    

Note the "*" in the F1 declaration.
0
 

Author Comment

by:tam031198
ID: 1166054
Thank you very much Nietod, you are the King !!!!!!
0
 
LVL 11

Expert Comment

by:alexo
ID: 1166055
>> What information? Just, the fact that it is an array and not an pointer to 1 item.
Yep... King :-)
0
 
LVL 3

Expert Comment

by:Norbert
ID: 1166056
Your function works but using your definition it does not know anything about the size of the array therefore it is better to pass the size also because the function then can handle arrays of different size

nietod: the '&' only was a typo - sometimes I should read what i have written before I hit the Submit button :-)
0
 
LVL 22

Expert Comment

by:nietod
ID: 1166057
Alex, I prefer "your highness."  
Nordbert, I figured it was a typo, the rest of the code suggested that.
0
 
LVL 11

Expert Comment

by:alexo
ID: 1166058
Nordbert, any relation to Dilbert?
0
 
LVL 3

Expert Comment

by:Norbert
ID: 1166059
Who is Dilbert ???
Nietod: Typos hapens to everyone :-)
0
 
LVL 22

Expert Comment

by:nietod
ID: 1166060
Mostly they happen to em.
0
 
LVL 11

Expert Comment

by:alexo
ID: 1166061
>> Who is Dilbert ???
Man, what planet did you live on in the last 4 years?
www.unitedmedia.com/comics/dilbert
0

Featured Post

[Webinar] Learn How Hackers Steal Your Credentials

Do You Know How Hackers Steal Your Credentials? Join us and Skyport Systems to learn how hackers steal your credentials and why Active Directory must be secure to stop them. Thursday, July 13, 2017 10:00 A.M. PDT

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Article by: SunnyDark
This article's goal is to present you with an easy to use XML wrapper for C++ and also present some interesting techniques that you might use with MS C++. The reason I built this class is to ease the pain of using XML files with C++, since there is…
IntroductionThis article is the second in a three part article series on the Visual Studio 2008 Debugger.  It provides tips in setting and using breakpoints. If not familiar with this debugger, you can find a basic introduction in the EE article loc…
The goal of the video will be to teach the user the difference and consequence of passing data by value vs passing data by reference in C++. An example of passing data by value as well as an example of passing data by reference will be be given. Bot…
The viewer will be introduced to the member functions push_back and pop_back of the vector class. The video will teach the difference between the two as well as how to use each one along with its functionality.
Suggested Courses

617 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question