?
Solved

Server Sockets

Posted on 1998-06-25
11
Medium Priority
?
179 Views
Last Modified: 2010-04-04
I'm working on this chat program using serversockets
I can get mutilple connetions to the server part but when i send a message from a client  i cant relay the message to the other connections.
How do i change to a different socket connection to send out  the message?
0
Comment
Question by:bbreaux
11 Comments
 

Author Comment

by:bbreaux
ID: 1355752
Edited text of question
0
 
LVL 4

Expert Comment

by:BoRiS
ID: 1355753
bbreaux

have you checked out the chat demo that comes with delphi...

Later
BoRiS

0
 

Expert Comment

by:fromager
ID: 1355754
0
VIDEO: THE CONCERTO CLOUD FOR HEALTHCARE

Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.

 

Author Comment

by:bbreaux
ID: 1355755
yes i have look at the example but it doesnt allow for mutiplte connections only pier to pier
0
 
LVL 4

Accepted Solution

by:
d003303 earned 300 total points
ID: 1355756
Yo,
you will have to hold a list of all connected clients that is updated in the OnClientConnect and OnClientDisconnect event handlers. Use AddObject(IntToStr(Socket.SocketHandle), Socket) to save the object in the string list. When a client disconnects, use Delete(IndexOfName(IntToStr(Socket.SocketHandle)) to remove him from the list.
To broadcast the incoming message, loop through the list and send all clients the message data (maybe you want to leave out the sender).

Slash/d003303
0
 

Author Comment

by:bbreaux
ID: 1355757
I have a array or records
could i just asign the sockethandle to a varible in my record

example:
 
myrecoord.handle :=socket.sockethandle

0
 

Author Comment

by:bbreaux
ID: 1355758
I have a array or records
could i just asign the sockethandle to a varible in my record

example:
 
myrecoord.handle :=socket.sockethandle

0
 

Author Comment

by:bbreaux
ID: 1355759
that works great next to the fact i cant figure out how to loop over the list and send to that user
0
 
LVL 4

Expert Comment

by:d003303
ID: 1355760
You could also use an array of records for that. I recommend a string list because it can hold a variable amount of users at run-time. With the array, you are limited to the arrayy bounds that is set at compile-time.
Loop throug the list with
for index := 0 to UserList.Count - 1
 do BroadcastMessage(TSocket(UserList.Objects[index]), Message);
where BroadcastMessage would send the chat message. You can cast UserList.Objects[index] to the appropriate socket you received if you need to.

Slash/d003303
0
 

Author Comment

by:bbreaux
ID: 1355761
I get an error when i use Broadcastmessage

undeclared identifier

0
 

Author Comment

by:bbreaux
ID: 1355762
i got it working thanks for the help
0

Featured Post

Industry Leaders: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

This article explains how to create forms/units independent of other forms/units object names in a delphi project. Have you ever created a form for user input in a Delphi project and then had the need to have that same form in a other Delphi proj…
In this tutorial I will show you how to use the Windows Speech API in Delphi. I will only cover basic functions such as text to speech and controlling the speed of the speech. SAPI Installation First you need to install the SAPI type library, th…
We’ve all felt that sense of false security before—locking down external access to a database or component and feeling like we’ve done all we need to do to secure company data. But that feeling is fleeting. Attacks these days can happen in many w…
Screencast - Getting to Know the Pipeline
Suggested Courses

850 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question