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I need an init string

I have a Zoom Fax/Modem 56Kx model 2849. It's made to run in K56flex mode, but I only connect in V.34 at 28800 bps. My ISP supports K56flex, and there are three numbers to get k flex access. I just recently updated my driver. If anyone can give me some valid init strings or any other kind of help, I would be greatly thankful. Remember, I want to connect in K56flex mode, so I need something that can make it work in that mode. Anything else besides init strings that could improve my connection speed from 28800 bps is really appreciated. Sorry, but I can't offer too many points because I just gave away 20 points for nothing.
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shintinsdas87
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shintinsdas87
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shintinsdas87Author Commented:
I NEED A REAL EXPERT TO ANSWER THIS FOR ME!!!!!!
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OttaCommented:
Modems are designed to work correctly, as purchased.
So, don't expect a "fancy" initialization-string.
Try 'AT&F' and try 'AT&F1' and try 'ATZ'.
One of these strings will handle over 90% of the modems
which are now being sold in retail outlets.

Otherwise, the ability to use higher-than-33600 speeds
depends on the hardware which the telephone-company
has between your modem and your ISP's modem.

Specifically, if too many "conversions" (analog-to-digital,
and/or digital-to-analog) are being done by their hardware,
the highest speed which is "negotiated" between your modem
and your ISP's modem will only be 33600,
no matter what initialization-string you use.

Ask your ISP -- they should know which telephone "exchanges",
i.e., the first three digits of a seven-digit number,
are capable of high-speed connections, i.e., if they know
that a whole exchange is "bad", and your telephone-number
is within that exchange, then you're out-of-luck.
Conversely, the fact that some(!) numbers in an exchange
are "high-speed-capable" does not *always* mean
that all numbers in that exchange have identical capabilities.
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shintinsdas87Author Commented:
THANKS A LOT!!!!!!!!!!! I HOPE THAT THE INFORMATION YOU GAVE ME WORKS OUT.
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OttaCommented:
If it doesn't, feel free to make make another posting
to the question.
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