Ignatz
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malloc() and fork()
When I call fork(), are all my dynamic memory pointers copied, and pointing to new memory addresses? Is this chunk of code correct? Please explain. Thank You.
int fork_func(void)
{
char *p;
p = (char *)malloc(100);
if (!fork()) {
/** some processing **/
free((void *)p);
}
free((void *)p);
return 0;
}
int fork_func(void)
{
char *p;
p = (char *)malloc(100);
if (!fork()) {
/** some processing **/
free((void *)p);
}
free((void *)p);
return 0;
}
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