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&lt;in&gt; is a String (not array of Strings) parameter in a method, and when this method is called, &lt;in&gt; is coming from a database via ResultSet.getString() . Any other ideas? <br />

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<in> is a String (not array of Strings) parameter in a method, and when this method is called, <in> is coming from a database via ResultSet.getString() . Any other ideas?


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Did you call the next method before assigning the String?<br />
Let's say you have a variable called result as ResultSet,<br />
<br />
you have to do result.next() first, then you can assign in to result.getString() if there's any row returned<br />

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Did you call the next method before assigning the String?
Let's say you have a variable called result as ResultSet,

you have to do result.next() first, then you can assign in to result.getString() if there's any row returned


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So you have something like, in=ResultSet.getString();<br />
ResultSet is not null, 'cos you'd get an Null pointer exception... (but it's still worth a check)<br />
Have you try to get the length() of the string, ie in.length(); and see what's the value.<br />
<br />
Chris.<br />

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So you have something like, in=ResultSet.getString();
ResultSet is not null, 'cos you'd get an Null pointer exception... (but it's still worth a check)
Have you try to get the length() of the string, ie in.length(); and see what's the value.

Chris.


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The string is not null and has a length because as my method is written it wouldn't reach to the point where in.charAt() is called. Anyway I printed the length to the standard output and it is 4.<br />

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The string is not null and has a length because as my method is written it wouldn't reach to the point where in.charAt() is called. Anyway I printed the length to the standard output and it is 4.


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Please forget the question. The exception was happening when StringBuffer.setCharAt() was called, and not on String.atChar(). My mistake. Sorry.<br />

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Please forget the question. The exception was happening when StringBuffer.setCharAt() was called, and not on String.atChar(). My mistake. Sorry.


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Well at least you found it :)<br />

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I have a String named in. When I call in.charAt(0) I get StringIndexOutOfBoundsExce<wbr />ption. Why is this happening when the String is neither null nor &quot;&quot;?
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I have a String named in. When I call in.charAt(0) I get StringIndexOutOfBoundsException. Why is this happening when the String is neither null nor ""?

String problem

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