• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 262
  • Last Modified:

formatting for Y2K

I am currently using the Lost_Focus event in a textbox and formatting the date as:
Format(y2kcheck$, "m/d/yyyy"), but if the user enters 03/03/00 the output is 3/3/1900,
How can I change the code to make it 3/3/2000?
Code please...
0
dtucker
Asked:
dtucker
  • 3
  • 2
1 Solution
 
percosolatorCommented:
What version of VB are you using (VB5 SP3, here)

Tried the following in the immediate window:

?format("03/03/00","mm/dd/yyyy")
03/03/2000

Put it at 2000, for me.  Any other information?
0
 
dtuckerAuthor Commented:
I am using vb4 16 bit.
I could even break down the date and replace 1900 with 2000 if there is not a FORMATing way to do it.
Code Please...
Thank you for your prompt response.
Dave
0
 
percosolatorCommented:
What we are seeing here is inherent behavior designed into the date datatype.

My understanding of how Microsoft decided to handle 2-digit years, was this.

any 2-digit year from 00 to 29 is considered 20th century (i.e. 2000, 2019, 2029)

any 2-digit year from 30 to 99 is considered 19th century (i.e. 1930, 1968, 1999)

(Tested them out here, and it worked as expected)

Try these examples (00,29,30,99) out and please post your results.  That will help us see what's going on to better solve your dilemma.
0
VIDEO: THE CONCERTO CLOUD FOR HEALTHCARE

Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.

 
clifABBCommented:
Also, what database are you using?  Perhaps the database isn't Y2K compliant?
0
 
dtuckerAuthor Commented:
My database is just a random file database, which isn't Y2K compliant.
if I type 3/3/00 I get 3/3/1900
if I type 3/3/30 I get 3/3/1930
So I have to find a way to check for the 00 in my date field and translate that to 2000, as well as 01 as 2001 etc.
Right now if someone types in 3/12/98 it returns 3/12/1998, so all is fine until the year 2000.
Any thought as how to do the check and conversion in vb4 16-bit?
0
 
percosolatorCommented:
Here is some sample code that I tested and believe will help you with your problem.

Put this code and put it in a test project.  If you have any questions, please post them.

-------------------------------------------------

Option Explicit

Private Sub Form_Load()

    MsgBox FixDate(CDate("1/1/00"))
    MsgBox FixDate(CDate("1/1/01"))
    MsgBox FixDate(CDate("1/1/99"))
   
    MsgBox FixDate(CDate("3/3/29"))
    MsgBox FixDate(CDate("3/30/30"))
    MsgBox FixDate(CDate("2/3/68"))
End Sub
Private Function FixDate(Date_ As Date) As String

    Dim strYear As String, _
        strDay As String, _
        strMonth As String
   
   
    strYear = Format(Date_, "yyyy")
    strMonth = Format(Date_, "mm")
    strDay = Format(Date_, "dd")
   
    If (strYear < "1930") Then strYear = strYear + 100
   
    FixDate = Format(strMonth & "/" & strDay & "/" & strYear, "mm/dd/yyyy")
       
End Function

------------------------------------
0

Featured Post

Concerto Cloud for Software Providers & ISVs

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!

Learn how Concerto can help you.

  • 3
  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now