aligning items in list box

Posted on 1998-08-12
Medium Priority
Last Modified: 2010-04-30
how do i align items in a list box.....
i  concatenate 3 fields and then add it to a list box but the next 3 does not align with the first....any way to align it....

Question by:wenchang
  • 2
LVL 14

Accepted Solution

waty earned 800 total points
ID: 1468642
To align items in a listbox, you have to set a fexed font (system)

Another solution is settings tabstops

Private Declare Function SendMessageLong Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, ByVal lParam As Long) As Long

Private Const LB_SETTABSTOPS = WM_USER + 19

Sub CBLTabStops(CBL As Control, nNbTab As Integer, nTab() As Integer)
    ' *** Create tabstop to aliogn columns
    ' nNbTab = Nbr of tabs
    ' nTab() = Size of each column in pixels

    Dim lResponse As Long

    lResponse = SendMessageLong(CBL.hwnd, LB_SETTABSTOPS,
     nNbTab, nTab(0))

End Sub

LVL 14

Expert Comment

ID: 1468643
I forgot to give you the way to write to column :

Sub CBLWriteCol(CBL As Control, ByVal nLigne As Integer, ByVal nCol As Integer, szCol As String)
    ' *** Write for a specific ling in a column
    Dim szLigne       As String
    Dim szNewLine     As String
    Dim lIndex        As Long
    Dim iIndice       As Integer
    Dim nPositionTab  As Integer
    Dim nPositionFin  As Integer
    szLigne = CBL.List(nLigne)
    lIndex = CBL.ItemData(nLigne)
    '*** Seek beginning of column
    nCol = nCol + 1
    nPositionTab = 1
    Do While nCol > 1
        nPositionTab = InStr(nPositionTab, szLigne, Chr$(9))
        If nPositionTab = 0 Then Exit Sub
        nPositionTab = nPositionTab + 1
        nCol = nCol - 1
    '*** End of column
    nPositionFin = InStr(nPositionTab, szLigne, Chr$(9))
    If nPositionFin = 0 Then
        nPositionFin = Len(szLigne)
        nPositionFin = nPositionFin - 1
    End If
    szNewLine = ""
    If nPositionTab > 1 Then szNewLine = szNewLine & Left$(szLigne, nPositionTab - 1)
    szNewLine = szNewLine & szCol
    If nPositionFin < Len(szLigne) Then szNewLine = szNewLine & Right$(szLigne, Len(szLigne) - nPositionFin)
    CBL.RemoveItem nLigne
    CBL.AddItem szNewLine, nLigne
    CBL.ItemData(CBL.NewIndex) = lIndex

End Sub

And finally, here is a way to add scrollbar

Private Declare Function SendMessageLong Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, ByVal lParam As Long) As Long

Sub CBLSetHScroll(CBL As Control, nLen As Integer, nAvgCharWidth As Integer)

   Dim lResponse  As Long
   lResponse = SendMessageLong(CBL.hwnd, LB_SETHORIZONTALEXTENT, nLen * nAvgCharWidth, 0&)

End Sub


Expert Comment

ID: 1468644
You will find great examples of using columns in a listbox at:


Click "Code Library" and then "List & Combo"

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