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Solved

how to print out list of lists

Posted on 1998-08-20
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Medium Priority
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Last Modified: 2010-03-05
.......
push(@$list{$_},$name);
......
how can I print out all elements of this list of lists? Thanks.
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Question by:tian
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3 Comments
 

Expert Comment

by:kaijen
ID: 1204422
I'm not sure what you're doin' with the push statement. I think $name should be something like ($name) or another slice.
Am I right?

In general printing LoLs works like:

@strArray = ("a;b;c;d", "e;f;g;h", "i;j;k" );

for $i ( 0 .. 2 )
{
  push @LoL, [ split /;/, $strArray[$i] ];
}

for ( @LoL )
{
  for ( @$_ )
    {
      print "$_\n";
    }
}

Best regards,
Kai.
0
 

Author Comment

by:tian
ID: 1204423
Thanks Kai,
I still can not solve it seeing your comment.(maybe i am too stupid)
In fact What I am trying to do is:(you can see my last question:"implement it in elegant way"for reference)

    ....
 foreach $f (@files){
    $name=$f;
    $open(FILE,$f) || die "cannot open";

    while(<FILE>){
      if(exists $pattern{$_}){
         push @{$list{$_}},$name; # push(@$list{$_},$name); doesnot work
      }
    }
}

   ....
 #then how to print content of the @list{pattern1} @list{pattern2}.......
 
0
 
LVL 5

Accepted Solution

by:
b2pi earned 200 total points
ID: 1204424
use strict;


my($i, $j, %list, $ndx);
$i = 0;
foreach $ndx (qw(a b c d)) {
    for ($j = $i; $j < $i +4;$j++) {
      push(@{$list{$ndx}}, $j);
    }
    $i += 4;
}

## Now print it
print "Printing:\n";
foreach $ndx (sort keys %list) {
    print "$ndx:";
    foreach (@{$list{$ndx}}) {
      print "\t$_\n";
    }
    for ($i = 0; $i <= $#{$list{$ndx}}; $i++) {
      print "\t$list{$ndx}->[$i]\n";
    }
    print "\n";
   
}

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