How to check if 2 or more applications are running?

I need a source code that will check if the application that my program launched by SHELL command is still running.  My program is a scheduler, two applications can run at the same time and what I need is to check if both these applications are still running.  I tried a code which I got from a book that checks one application at a time, this does not suit my program because it inhibits the running of other scheduled applications.

Ex.  App1 - should run at 11:00AM
     App2 - should run at 11:01AM

Launch App1 at 11:00AM then a loop that will check if it still running.  App1 is still running at 11:01AM but my program sees that App2 should be run at 11:01AM thus it will run App2 at 11:01AM.  Then the program should check if these two applications are still running.

I hope someone can help me.
Thank you.
MokMokAsked:
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watyConnect With a Mentor Commented:
Const SYNCHRONIZE = &H100000
Const INFINITE = &HFFFFFFFF
Private Declare Function OpenProcess Lib "kernel32" (ByVal dwDesiredAccess As Long, ByVal bInheritHandle As Long, ByVal dwProcessId As Long) As Long
Private Declare Function CloseHandle Lib "kernel32" (ByVal hObject As Long) As Long
Private Declare Function WaitForSingleObject Lib "kernel32" (ByVal hHandle As Long, ByVal dwMilliseconds As Long) As Long

           
Dim pId As Long, pHnd As Long '

pId = Shell("Notepad", vbNormalFocus) '

pHnd = OpenProcess(SYNCHRONIZE, 0, pId) ' get Process Handle
If pHnd <> 0 Then
   Call WaitForSingleObject(pHnd, INFINITE) ' Wait until shelled
              prog ends
   Call CloseHandle(pHnd)
End If

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MokMokAuthor Commented:
I have already tried this code.  The problem I get is that it waits for my first application to finish.  My first application has a long run time.  What I need is something that is flexible enough to run two application at the same time and performs a check if it is still running.
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watyCommented:
One solution, is storing the Pid returned by the shell and periodically use OpenProcess API to see if it is still in memory <>0.

That's all.
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