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put in pointer address manually

Posted on 1998-09-08
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Last Modified: 2010-04-02
I have an unsigned short variable (result) which stores the address to a table, this variable holding the address is all I have to work with. All the fields are text data type. I want to take a char pointer and point it at the first field of the table but it squawks when I try to assign an unsigned short to a char *.
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Question by:jtm082698
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milenvk earned 50 total points
ID: 1172289
That's because a pointer usually takes twice more memory than an unsigned short. Consider using with char* or void* or whatever pointer you'd like instead of using unsigned short. It really depends on the operating system that you are working with. Also you can work around the problem with the compiler warning or error if you are using explicit type cast, i.e. :

void fo(unsigned short table)
{
  char* pc = (char*) table;
  //....
}
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by:jtm082698
ID: 1172290
Okay, but when I try to use it, i.e.:

ptrChar = (char*)result;
                              
for(i=0;i<sizeof(Record);i++)
{
Record[i] = *ptrChar;
ptrChar++;
}  

the compiler gives an unhandled access error.

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by:milenvk
ID: 1172291
If you are using C string you better loop up to the string length. The program crashes because you are trying to access a memory that you did not allocated. Use

for(i=0;i<sizeof(Record) && i < strlen(ptrChar)+1;i++)

for the loop.
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by:ozo
ID: 1172292
How are result and Record declared?
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by:dpms
ID: 1172293
result is an unsigned short variable and Record is a char [50]
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by:ozo
ID: 1172294
Is sizeof(unsigned short) <= sizeof(char *) on your machine?
Where did result get assigned with something you think would make (char*)result meaningful?
Could you be thinking of (char *)&result ?
But that would make ptrChar+=sizeof(Record) point beyond the end of result, so that doesn't make sense either.
Why isn't result declared as a char* ?
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by:milenvk
ID: 1172295
Even if unsigned short can handle a pointer, sizeof(Record) returns 50 and probably you are trying to access a memory that you did not allocated, i.e. if the result is a pointer to a memory of 30 allocated bytes, when i becomes 30 your program will crash with an access exception, like it does.
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