Replacing the Last Three Characters

In a stored procedure, a parameter @input is passed that contains '.htm' on the end.  In the sp I would like to replace the 'htm' with 'doc' and use it as the value of another input.
Is it possible to replace these characters?  They would always be on the end although the beginning of the parameter may contain 'htm' as well.  But I would want to replace the ending characters.
Thank you.
jgcarmichAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

bretCommented:
This will replace the last 4 characters of a string with ".doc":

select @input = stuff(@input, char_length(@input)-3,4,".doc")
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server

From novice to tech pro — start learning today.