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Replacing the Last Three Characters

Posted on 1998-09-14
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Last Modified: 2010-03-19
In a stored procedure, a parameter @input is passed that contains '.htm' on the end.  In the sp I would like to replace the 'htm' with 'doc' and use it as the value of another input.
Is it possible to replace these characters?  They would always be on the end although the beginning of the parameter may contain 'htm' as well.  But I would want to replace the ending characters.
Thank you.
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Question by:jgcarmich
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bret earned 400 total points
ID: 1090034
This will replace the last 4 characters of a string with ".doc":

select @input = stuff(@input, char_length(@input)-3,4,".doc")
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