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wordwrap code

Posted on 1998-09-15
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Last Modified: 2008-03-06
Does anyone have (or willing to find) some code for chopping up a string WordWrap style?  

I want to take the string as it appears in the label on the form and send it line by line to the printer object.  I've got printer.currentx, just need to send the string in and print lines out.

Yes, this is simple, but I'm missing something stupid and have to move on...  Why don't I just print the form?  VB doesn't support printing of forms larger than your screen.  Ah well.
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Question by:kmarf
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mark2150 earned 50 total points
ID: 1435164
Here's a block of code (way too big for what should be a trivial function) that does what you want.

    Call PrintLongText(Text2.Text)

Sub PrintLongText(LongText As String)
'
' This procedure prints a text stream to a printer and
' ensures that words are not split between lines and
' that they wrap as needed.
'
    Printer.CurrentX = leftedge
    Do Until LongText = ""
'
' current word is null
'
        word$ = ""
'
'        look for crlf in text
'
        marker1 = InStr(LongText, vbCrLf)
'
' Look for space in line of text
'
        marker = InStr(LongText, " ")
'
' Give preference to CRLF if present
'
        If marker1 < marker Then
            crflag = True
            marker = marker1
        Else
            crflag = False
        End If
'
        If marker > 0 Then
'
' If we've found a space, get left part as current word and strip
' it off the line
'
            word$ = LTrim$(RTrim$(Left$(LongText, marker - 1)))
            LongText = Right$(LongText, Len(LongText) - marker)
            If Left$(LongText, 1) = Chr$(10) Then LongText = Right$(LongText, Len(LongText) - 1)
        Else
'
' Only one word left, take it and close out line of text
'
            word$ = LTrim$(RTrim$(LongText))
            LongText = ""
        End If
'
' Force a newline if we're getting to the end of the current line
'
        If Printer.TextWidth(word$) + Printer.CurrentX > rightedge - Printer.TextWidth(word$) Then crflag = True
'
' Print a space and the next word of the message
'
        If crflag = True Then
            Printer.Print word$
            Printer.CurrentX = leftedge
        Else
            Printer.Print word$; " ";
        End If
'
' Repeat until line of text is gone
'
    Loop
    Printer.Print
    Printer.CurrentX = leftedge
End Sub

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by:kmarf
ID: 1435165
Well, it doesn't seem to be printing more than the first line, and I seem to be getting different fonts (or missing labels) each time I print.

Very likely, however, that I've gotten something flubbed up beforehand.
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Expert Comment

by:mark2150
ID: 1435166
Watch the LONGTEXT var inside the routine. You should be able to single step it and see it build the line a word at a time.

It expects vbCRLF's as delimiters, a vanilla CR/LF pair will get it confused.
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