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Shell scripts

bsufs asked
Medium Priority
Last Modified: 2010-04-22
How do you get a bash shell script to run commands such as passwd where the user is prompted for input?  I want to run the command all in one go, with the relevant inputs provided in the script itself.

Thanks in advance.
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You have to use expect(1) to do that.


Could you tell me a bit more about Expect - what is it, how do I use it, etc.

Thanks very much.
man expect



Is this the only way to do it, because we don't appear to have expect.

What I am really looking for is a way of changing a password from a script.  The passwd command prompts you for inputs so it is no good calling this from a script.
Did you install the package?  It comes with most Linux distributions.

And yes, this is basically the only technique for doing it, unless you are root in which case you can just manipulate /etc/passwd directly.

What's exactly your problem calling passwd from within a script?
Expect is in /usr/bin.

Alternatively write a small C program to get your input along the lines of
"scanf "%s",&name; return name" - and use this in your script. Not very portable, but a quick fix anyway...


I can manipulate /etc/passwd directly but this doesn't help when setting the password because it needs to be encrypted.  The idea was that I would use a script to insert a new entry directly in /etc/passwd and then change the password.

The problem with calling passwd from within a script is that it needs inputs from the user.  I want to call it from within a script and complete the whole process, i.e. change the password, using information from the script and not prompting for inpts.  Basically I just want to run a script telling it to change the password of user xyz to abc and let it run on its own without requiring extra input.
Your problem is that you DO need a tty (or pseudo tty) because passwd command reads directly from it and not from stdin... I can send you a little sample if you want...

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