piping input to passwd

I'm using Redhat 5.1.
I want to set a user's password from a shell script without and human intervention.

I have tried this (and various others):

echo -e "foo123\nfoo123" | passwd foobar

But I get this:
New UNIX password: Retype new UNIX password:
New UNIX password:
New UNIX password:
passwd: Conversation error

Any ideas?

Many Thanks!

mag062397Asked:
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marcelofrCommented:
passwd command reads from the tty DIRECTLY, not from stdin so you need at least a pseudo tty. The following expect script may help you:

#!/usr/bin/expect
set oldpass [lindex $argv 0]
set newpass [lindex $argv 1]
spawn /usr/bin/passwd
expect word:
sleep 1
send $oldpass\r
expect word:
sleep 1
send $newpass\r
expect word:
sleep 1
send $newpass\r

Put this stuff in a script, chmod +x it and call it passing old and new passwords as parameters.

Good Luck
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mag062397Author Commented:
Thank you I got it working.  The only thing I had to add was either a "sleep 1" or an "expect success" at the end of the script.  For some reason the script would end and I think the passwd program would think it was killed or something so it would not make the change.  By putting in one more expect string the script waits until passwd completes its task.  A sleep 1 also worked; however I'm going to stick with the expect success.

Thanks again.
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