Random numbers

I'm writting a simple game in which the user has to touch an item that ramdomly moves to a different place on the screen each time it is touched.  Right now the game is incredibly too easy because the object always comes back into the game in a spot very close to the place it was already at.  Here is the code I used:
//begin code
#include <time.h>
time_t seconds;

srand((unsigned int) seconds);

xposition = rand() % (HIGH - LOW + 1) + LOW;
yposition = rand() % (HIGH - LOW + 1) + LOW;
//end code
Does anyone know a better way to get a random number that isn't always close to the number it was before?
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viktornetConnect With a Mentor Commented:
How about using only the high parameter...as follows

xposition = rand() % (HIGH);
yposition = rand() % (HIGH);

If you supply which is the Height and which is the Width it would be even easier to supply an answer..

xposition = rand() % (WIDTH);
yposition = rand() % (HEIGHT);

This is a better solution...I don't know what your game is so...this would be iot..

SileNcerAuthor Commented:
That made the code look better, but the object is still being ramdomized in a spot close to where it was before.  I was trying to make a Nibbles game (your a worm and you have to eat little blocks.)
I think the problem is that when the worm eats the block, the randomizing seed is too close to the previous in the split second the process occurs. Maybe you can help me now?
SileNcerAuthor Commented:
Okay, I fixed it!!!  It seems that the x value wasn't really ramdomizing so I just did this:

xposition = rand() % (WIDTH);
yposition = rand() % (HEIGHT);
xposition = rand() % (WIDTH);

By putting in the ramdom x value twice, it worked :) don't know why.  Thanks a lot for your help!!!
Are you doing the srand every time you get a new position?
If so, that's probably the problem.
You should call srand just once at the start, then just repeatedly call rand() without reseeding it again.
SileNcerAuthor Commented:
That worked!  Yeah, I guess I didn't need that in the function.  Thanks for helping me.
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