Want to win a PS4? Go Premium and enter to win our High-Tech Treats giveaway. Enter to Win

x
?
Solved

Converting Dir's to \..\..\

Posted on 1998-10-03
3
Medium Priority
?
187 Views
Last Modified: 2010-04-30
If Name = "a111a111a111" Then Exit Sub

Hi,
I would like to do the following,
(real sorry for the points)

How do you convert a string with a file path from this C:\Canada\ONT\Ottawa
to this
..\..\
assuming I wanted to add a Link to Canada while the inital HTML file was saved in Ottawa.

Again, sorry for the points.
0
Comment
Question by:idcanada
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
3 Comments
 

Accepted Solution

by:
jfayling earned 120 total points
ID: 1437909
I use a function that I wrote that will split up a a string by a userdefined character.


I would do something like this

dim total as long
dim tmpArray as variant

  total=parsestring(tmpFilePath,"\",tmpArray)

 

  using the example you gave us:
      total = 3
      tmpArray(0)="C:"
      tmpArray(1)="Canada"
      tmpArray(2)="ONT"
      tmpArray(3)="Ottawa"

  notice that the 3 was the number of \ is found!

Good Luck!

Here is the function:

Function ParseString(LookIn As String, Search As String, ByRef ReturnArray As Variant) As Long
'
' Function Name:    ParseString
'
' Author:           JF Software (Jason R. Fayling)
'                   jfayling@glasscity.net
' Date:             1/10/97
'
' Inputs:           LookIn  (STRING)        String to use
'                   Search  (STRING)        What to look for in string
'                   ReturnARRAY (VARIANT)   Any found will be stored here
'
' Outputs:          ParseString (INTEGER)   Number of items in ReturnArray
'                                           starting with zero. If no item
'                                           was found, then returns -1
'
'                   ReturnArray (VARIANT)   Found items from string
'
' Purpose:          ParseString will take a string and seperate it into
'                   user-defined parts.
'                   Example:
'
'                       Dim i as Integer
'                       Dim j as integer
'                       dim Temp as variant
'
'                       i=ParseString("10/24/97","/",Temp)
'
'                       for j=0 to i
'                           msgbox Temp(j)
'                       next j
'
'                   This will display 10 then 24 then 97
'
'
' You are granted royalty free use of this code in your projects.   You may
' remove this comment block in your own projects.   If you intend to redistribute
' this function as part of a library or outside of your own VB project then you
' must leave this block in tact.


Dim X As Long
Dim start As Long
Dim pos As Long
Dim track As Long
ReDim TempHolder(Len(LookIn)) As String


    track = 0
    start = 1
   
    ' Start at the beginning of string and move down until it finds
    ' character it is looking for. Once it finds the character, it
    ' places everything before it and after the last found item into
    ' a new element in an array
   
    Do
        pos = InStr(start, LookIn, Search, vbBinaryCompare)
        If pos > 0 Then
            TempHolder(track) = Mid$(LookIn, start, (pos - start))
            track = track + 1
            start = pos + Len(Search)
        End If
    Loop Until pos = 0
   
    ' Make sure everything has been copied into Temp array
    TempHolder(track) = Mid$(LookIn, start, Len(LookIn))
       
    ReDim tempholder2(track)
   
    ' Move only elements with data in them
    For X = 0 To track
        tempholder2(X) = TempHolder(X)
    Next X
   
    Erase TempHolder
   
    ' Return Array is a variant so it can be passed an array
    ReturnArray = tempholder2
   
    If track = 0 Then
        ' Nothing was found
        ParseString = -1
    Else
        ParseString = track
    End If

End Function


0
 
LVL 4

Author Comment

by:idcanada
ID: 1437910
Thats a very good function,
although, would you mind helping me achieve the task asked in the Question?

I have a few problems,
How to read the last array?
(contains the filename)
and convert the rest to \..\..\ ???


0
 
LVL 4

Author Comment

by:idcanada
ID: 1437911
Okay,

I can read the last array.


0

Featured Post

Industry Leaders: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction While answering a recent question about filtering a custom class collection, I realized that this could be accomplished with very little code by using the ScriptControl (SC) library.  This article will introduce you to the SC library a…
I was working on a PowerPoint add-in the other day and a client asked me "can you implement a feature which processes a chart when it's pasted into a slide from another deck?". It got me wondering how to hook into built-in ribbon events in Office.
Show developers how to use a criteria form to limit the data that appears on an Access report. It is a common requirement that users can specify the criteria for a report at runtime. The easiest way to accomplish this is using a criteria form that a…
This lesson covers basic error handling code in Microsoft Excel using VBA. This is the first lesson in a 3-part series that uses code to loop through an Excel spreadsheet in VBA and then fix errors, taking advantage of error handling code. This l…
Suggested Courses

610 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question