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regex

Posted on 1998-10-03
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Last Modified: 2010-03-05
The below two snippets of code should do the SAME thing, however the first works and the later one doesn't. What is wrong with my regex in the second?

--- This WORKS: ----------------------------
 if (($a =~ /\//) && ($b =~ /\//)) {
   ($tempA,$junk) = split(/\//,$a);
   ($tempB,$junk) = split(/\//,$b);
   print "($tempA : $tempB)\n";
 }
--------------------------------------------

---  This DOESN'T: -------------------------
 if (($a =~ /(.*)\//) && ($b =~ /(.*)\//)) {
   print "($1 : $2)\n";
 }
--------------------------------------------
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Question by:rw263
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3 Comments
 
LVL 84

Expert Comment

by:ozo
ID: 1205128
Nothing sets $2, and the $1 from ($a =~ /(.*)\//) is overwritten by ($b =~ /(.*)\//))
You might try something like
print "($tempA : $tempB)\n" if (($tempA)=($a =~ /(.*)\//)) && (($tempB)=($b =~ /(.*)\//));
0
 

Accepted Solution

by:
ItamarC earned 20 total points
ID: 1205129
The comment from 'ozo' was right. If you want to use $1 and $2, you need to have all this in one matching expression.
The code below will do what you need. I used "x_x" to separate $a and $b. You can change it to what you like.

if ( "${a}x_x$b" =~ /(.*)\/.*x_x(.*)\// ) {
  print "($1 : $2)\n";
}

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LVL 84

Expert Comment

by:ozo
ID: 1205130

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