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An easy question for the more experienced than I

Posted on 1998-10-05
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We are dealing with for loops in class and we have to write a program to find the factorial of 1-10, I had the factorial part right by simply doing this
for(x=1;x>=10;x--)
 {
  product=product*x
  cout>>product<<'\n
 }
But I cant get it to say the factorial of 2 is " the factorial of 3 is ", those have to be incorporated in another for loop somehow. Can anyone please help.
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Question by:truancy
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5 Comments
 
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Expert Comment

by:Grailman
ID: 1174452
Slight problem w/ the loop:

   set x equal to 1
   as long as x is greater than or equal to 10 (it ain't so!)
   decrease x by 1 on each pass through the loop

Can't work that way. Also I'll assume the missing ';' after the two lines inside the loop are typos as is the '>>' which should be '<<'.   ;-)

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LVL 1

Expert Comment

by:Grailman
ID: 1174453
Slight problem w/ the loop:

   set x equal to 1
   as long as x is greater than or equal to 10 (it ain't so!)
   decrease x by 1 on each pass through the loop

Can't work that way. Also I'll assume the missing ';' after the two lines inside the loop are typos as is the '>>' which should be '<<'.   ;-)

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Accepted Solution

by:
Booth882 earned 10 total points
ID: 1174454
you dont need a new loop, just add to your output line in the loop you already have, like

cout << "the factorial of " << x << " is " << product << '\n';

because x is the value and product is the factorial.
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Author Comment

by:truancy
ID: 1174455
Actually the semicolons are what we use in Borlands Turbo C++, I dunno about anything else.....and ya they are typos, I was in a hurry I know which way they go =), anyway thanks for the help, I will try the proposed answer tomorrow in class.
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Expert Comment

by:Booth882
ID: 1174456
howd it go truancy?
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