Solved

Find and Replace Solution??????

Posted on 1998-10-06
3
104 Views
Last Modified: 2010-04-30
I want to find a string at a predetermined location (say 15)in a record,
grab that string length (say 35) and replace it with a string.

Thanks Fred
0
Comment
Question by:gosportlad
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
3 Comments
 
LVL 14

Expert Comment

by:waty
ID: 1438358
Use the following function :

Function ReplaceString(sSearch As String, sSearchFor As String, sReplaceWith As String) As String
   ' *** Searches the sSearch variable for sSearchFor
   ' *** and replaces it with sReplaceWith.

   On Error GoTo ERROR__ReplaceString

   Dim lFoundLoc        As Long   ' Location of match.
   Dim lLenRemove       As Long   ' Length of string being replaced.

   ' *** Set length of original text to skip.
   lLenRemove = Len(sSearchFor)    ' Set location of match.

   lFoundLoc = InStr(1, sSearch, sSearchFor)

   ' If sSearchFor isn't found in sSearch
   ' just return the original string.
   If lFoundLoc = 0 Then
      ReplaceString = sSearch
      ' If match is found, return original string up to match
      ' location, concatenate new text, and search the rest of
      ' the string recursively for additional matches.
   Else
      ReplaceString = Left(sSearch, lFoundLoc - 1) & sReplaceWith & ReplaceString(Mid(sSearch, lFoundLoc + lLenRemove), sSearchFor, sReplaceWith)
   End If

EXIT_ReplaceString:
   Exit Function

ERROR__ReplaceString:
   ' Print error to Debug window and don't interrupt query.
   Debug.Print "Error Replacing String """ & sSearchFor & """ with """ & sReplaceWith & """ in text """ & sSearch & """"
   ' If there is an error, return original string
   ' and exit the function.
   ReplaceString = sSearch
   Resume EXIT_ReplaceString

End Function

0
 

Author Comment

by:gosportlad
ID: 1438359
Thanks for your response, but I want to tell the function where the string is located (to validate) within each record.

Regards Fred
0
 
LVL 14

Accepted Solution

by:
waty earned 50 total points
ID: 1438360
So do as follow :

Mid(sYourString, 15, 35) = sYourNewString
0

Featured Post

Free Tool: Postgres Monitoring System

A PHP and Perl based system to collect and display usage statistics from PostgreSQL databases.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction I needed to skip over some file processing within a For...Next loop in some old production code and wished that VB (classic) had a statement that would drop down to the end of the current iteration, bypassing the statements that were c…
There are many ways to remove duplicate entries in an SQL or Access database. Most make you temporarily insert an ID field, make a temp table and copy data back and forth, and/or are slow. Here is an easy way in VB6 using ADO to remove duplicate row…
As developers, we are not limited to the functions provided by the VBA language. In addition, we can call the functions that are part of the Windows operating system. These functions are part of the Windows API (Application Programming Interface). U…
Get people started with the process of using Access VBA to control Outlook using automation, Microsoft Access can control other applications. An example is the ability to programmatically talk to Microsoft Outlook. Using automation, an Access applic…

749 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question