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Help:Make the 1st col of ListView a TreeView?

Posted on 1998-10-09
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Last Modified: 2010-04-30
I'm trying to simulate a message board similar to that used in the Outlook Express newsreader which has a ListView control with the first column appearing in a TreeView format. Is there a control that does this automatically or is is done manually? Either way, could someone please let
me know where to find the control or how to add the tree structure to the first column?
Any help would be greatly appreciated.
Shi Jun
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Question by:shijun
3 Comments
 
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Expert Comment

by:TheAnswerMan
ID: 1439168
Send me a screen shot of what you are talking about..
Myxlplick@msn.com
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Author Comment

by:shijun
ID: 1439170
Dear hanzala,
Thank you but I think you may misunderstand or minimize this problem. You can use Outlook Express and look what the news looks like. And the tree view can displayed in any position, as well as in 1st col.If I follow you idea I think I should combine a tree view and some listviews. Thank you any way. Shi Jun

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Accepted Solution

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ameba earned 100 total points
ID: 1439172
' declarations, in module
Public Type LVITEM
    mask As Long
    iItem As Long
    isubitem As Long
    State As Long
    stateMask As Long
    pszText As String
    cchTextMax As Long
    iImage As Long
    lParam As Long
    iIndent As Long
End Type
Public Const LVM_SETITEM = (LVM_FIRST + 6)
Public Const LVIF_INDENT = &H10&

' in form
' add listview, two columns, and add some items
' in debug window (or commandbutton) try:
' setindent(2,1)
Private Sub SetIndent(ByVal lIndex As Long, ByVal lIndent As Long)
    ' lIndex is 1-based; just pass the ListItem's .Index property
    ' lIndent is the amount of indentation desired; the unit of
    '         measurement is the width of the list item's image.
    Dim LVI As LVITEM
    Dim lRet As Long
    With LVI
       .iItem = lIndex - 1 ' winapi index is 0 based, VB is 1 based
       .mask = LVIF_INDENT
       .iIndent = lIndent
    End With
    lRet = SendMessage(ListView1.hwnd, LVM_SETITEM, 0, LVI)
End Sub


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