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how to read cdlabels

in a drivelistbox it doesn't say d: [label]
but only d: when I read drive1.drive
if you read drive1.drive when you've selected a harddisk it does return c: [c-drive] but not when accessing a cdrom..
how can I find out the label of the drive?
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fax
Asked:
fax
1 Solution
 
MikeP090797Commented:
Here is a code i found somewhere, don't remeber where:

The GetVolumeInformation API call is used to retrieve information about hard drives, floppy drives,
and even CD-ROM drives. Notice how your Windows CD player can recognize which CD is
inserted? It is using the serial number of the CD-ROM (obtained with this API call) to make this
determination. Just substitute the drive letter where it currently says "F:\" and you can check on
any of your drives.

The code that follows will return the serial number (as a long), as well as the volume name and
volume type, such as FAT. However, the text in the returned strings is ended with a null character -
chr$(0). That's the reason for the InStr call -- it only shows the portion of the string up to the null
character. If you don't do that, the DLL showing the MsgBox interprets the null character as the
end of line and no further text is displayed.

Option Explicit Private Declare Function GetVolumeInformation Lib "kernel32" Alias "GetVolumeInformationA" (ByVal lpRootPathName As String, ByVal lpVolumeNameBuffer As String, ByVal nVolumeNameSize As Long, lpVolumeSerialNumber As Long, lpMaximumComponentLength As Long, lpFileSystemFlags As Long, ByVal lpFileSystemNameBuffer As String, ByVal nFileSystemNameSize As Long) As Long
                     
Private Sub cmdTest_Click()
 Dim iSerialNum As Long
 Dim sVolumeLabel As String
 Dim sVolumeType As String
 Dim iRetVal As Long
 sVolumeLabel = Space(255)
 sVolumeType = Space(255)
 iRetVal = GetVolumeInformation("f:\", sVolumeLabel, Len(sVolumeLabel), iSerialNum, 0, 0, sVolumeType, Len(sVolumeType))
 MsgBox "Disk Serial Number: " & iSerialNum & vbCrLf & "Volume Type: " & Left$(sVolumeType, InStr(sVolumeType, Chr$(0)) - 1) & vbCrLf & "Volume Label: " & Left$(sVolumeLabel, InStr(sVolumeLabel, Chr$(0)) - 1)
End Sub
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mcixCommented:
Great answer MikeP!

For more info about this look here:

http://www.mvps.org/vbnet/code/shell/cdexists.htm
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