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QuickTake 150 Power supply

What is the polarity of the plug fitting the external power supply outlet in the camera body of a QuickTake 150 camera?

The number of the Apple part is (M2851LL/A).

I have several AC/DC adapters and would like to utilize one of them for this purpose. It's important to know the polarity of the plug.
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topacki
Asked:
topacki
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1 Solution
 
rjhawkinCommented:
Not only would you need to know the voltage and polarity, but you would also need to know how many Miiliamps that the device is rated at. Oterwise you run a risk of either under or overpowering it.
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AureliusCommented:
This is from the apple spec sheet for the QT 150.  No polarity specified, but there is a recommended optional powersupply from a PowerBook range.

Power
*      Includes three AA lithium batteries
*      Supports three 1.5V AA, R6P, LR-6, or SUM-3 NiCad or lithium batteries
*      Optional AC adapter (use only the QuickTake AC adapter M2851LL/A or the Macintosh PowerBook AC Adapter M4662LL/A)
*      Optional QuickTake Battery Booster Pack (M265G/A)
Note: 1.5 V Alkaline batteries are NOT compatible with the QuickTake 150 camera and can damage the camera if used.
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topackiAuthor Commented:
I'm aware of the possibility of using a power supply from the Powerbook. I'm aware of the caution about the use of alkaline batteries. I'm also aware of the requirement for a suitable amount of current capacity in the AC adapter.

I've posted a question and am still seeking the answer to that question.
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AureliusCommented:
don't know about polarity.  B positive maybe?  ;)
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paulvaneykelenCommented:
All of apple's powersupplies using a peg are:

peg: positive
shield: negative.

The point made in previous comments about amps etc. are very valid. It may not worth it using a third party adapter if you can pick up a cheap apple power supply in many of the apple stores.
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topackiAuthor Commented:
I did try the URL provided and got an error message. Apple does change the location of pages and this may be why. I would have liked to have a document from Apple on the subject of polarity.
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