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Pulling out '0' and '1' from a byte

Posted on 1998-10-18
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Last Modified: 2010-04-30
Is there a easy way of telling what bit's are set in a byte?
Can someone please give me an example of a function that takes a byte (0-255) as input and leaves perhaps a string containing 8 chars i.e "00101101" as a result?
I need to test if certain bit's are set, for example value 4 (the third from the right) ignoring other bit's that are set.
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Question by:rakkas
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4 Comments
 
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Accepted Solution

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schild earned 400 total points
ID: 1440510
try this, its working


Private Function ByteToBool(ByVal ByteVal As Byte) As String

    Dim Index As Integer
   
    For Index = 1 To 8
        ByteToBool = IIf(ByteVal And 1, "1", "0") & ByteToBool
        ByteVal = ByteVal / 2
    Next
   
End Function


Good Luck
Schild
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Expert Comment

by:Poddy
ID: 1440511
I would recommed using the And operator.

To test for bits being set, take the decimal value of the bit, and AND it against the tested value.

If it is set it will return the value that you are testing for, if not, it will return zero

Bracket the AND expression or you may get strange results (AND has lower priority than =)

So

(7 and 4)  = 4
(8 and 4)  = 0

etc



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Author Comment

by:rakkas
ID: 1440512
Thanks, Poddy and schild.
You saved my day!!!
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Expert Comment

by:namiesiao
ID: 5414596
The above doesnt seems to work with some numbers. Take 100 for example. I've modified it a bit into the following code. Thanks for your code though, schild.

Public Function ByteToBin(ByVal ByteVal As Byte) As String
Dim Index As Integer

For Index = 1 To 8
    ByteToBin = IIf(ByteVal Mod 2, "1", "0") & ByteToBin
    ByteVal = ByteVal \ 2
Next
End Function
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