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DB SQL Text String Question

Posted on 1998-10-27
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Last Modified: 2010-04-30
I've got a input field for a last name. I built an SQL statement to pull this field and search a DB for the closest match. How do I account for the (') in a last name???

For example, when a user inputs, say, O'Malley (Gets assigned the variable, SelectUser), the program errors because of the ('). My SQL statement looks like this:

               strSQL = "Select * from PHONEDB WHERE [Last Name] Like '" & SelectUser & "*'"
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Question by:sehenkel
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vmano earned 50 total points
ID: 1441803
use double quotes around '
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Expert Comment

by:vmano
ID: 1441804
here is more info:
Single quotation marks ('), double quotation marks ("), and the pipe symbol (|) are all special characters in SQL. Double up the quotation marks or, if you have only one type of quotation mark (single or double) in your data, use the other one as the delimiter.All other characters are handled as is.

let me know if this helps,
vmano
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Author Comment

by:sehenkel
ID: 1441805
Edited text of question
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Author Comment

by:sehenkel
ID: 1441806
Not sure if I follow what you are saying. Are you saying the the ("), (') and (|) are interchangeable? I tried the change but it did not work. Here's more code so you can see:


SelectUser = UCase(lblLastName.text) 'Assign variable from input field
strSQL = "Select * from PHONEDB WHERE [Last Name] LIKE ' " & SelectUser & "* ' " 

'Search Phone Database
Set DBPhones = OpenDatabase(pDBFileName)
Set RSPhones = DBPhones.OpenRecordset(strSQL, dbOpenSnapshot)
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Expert Comment

by:vmano
ID: 1441807
OK. here is the code to convert your SQL:
   
   Dim nPos       As Integer
   Dim sTmp       As String
   Dim sSQL       As String

  strSQL = "Select * from PHONEDB WHERE [Last Name] LIKE ' " & SelectUser & "* ' " 
   sTmp = sSQL
   nPos = InStr(1, sTmp, "'")
   While nPos <> 0
      sTmp = Mid(sTmp, 1, nPos - 1) & "'" & "'" & Mid(sTmp, nPos + 1)
      nPos = InStr(nPos + 2, sTmp, "'")
   Wend
   strSQL = sTmp
   MsgBox strSQL

after this conversion your SQL should work fine.

let me know if  this helps,
vmano
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Expert Comment

by:vmano
ID: 1441808
a correction to the above comment.just replace sSQL with strSQL.
sorry for the confusion.

vmano
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Author Comment

by:sehenkel
ID: 1441809
Ok, after the coversion, my SQL statement looks like this (inputting O'Malley as a last name):

    Select * From PHONEDB WHERE [Last Name] LIKE "O"MALLEY*"

When trying to open the recordset, I get a 3075 error
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Author Comment

by:sehenkel
ID: 1441810
Ok, after the coversion, my SQL statement looks like this (inputting O'Malley as a last name):

    Select * From PHONEDB WHERE [Last Name] LIKE "O"MALLEY*"

When trying to open the recordset, I get a 3075 error
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Expert Comment

by:vmano
ID: 1441811
i think your SQL statement should be:
strSQL = "Select * from PHONEDB WHERE [Last Name] LIKE " & SelectUser & "*"
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Author Comment

by:sehenkel
ID: 1441812
The SQL line I typed was what the value of the srtSQL variable was when debugging. In the code, my line reads like this:

strSQL = "Select * from PHONEDB_CT WHERE [Last Name] LIKE '" & SelectUser & "*'"

When debugging (inputting in O'Malley into the program) it looks like this:

Select * From PHONEDB WHERE [Last Name] LIKE "O"MALLEY*"

Sorry, I should have made that clearer.
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Author Comment

by:sehenkel
ID: 1441813
The SQL line I typed was what the value of the srtSQL variable was when debugging. In the code, my line reads like this:

strSQL = "Select * from PHONEDB_CT WHERE [Last Name] LIKE '" & SelectUser & "*'"

When debugging (inputting in O'Malley into the program) it looks like this:

Select * From PHONEDB WHERE [Last Name] LIKE "O"MALLEY*"

Sorry, I should have made that clearer.
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Expert Comment

by:vmano
ID: 1441814
some problem with your SQL.try this (just cut and paste):
strSQL = "Select * from PHONEDB_CT WHERE [Last Name] LIKE '" & SelectUser & "'*"

this should do it.

vmano
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Author Comment

by:sehenkel
ID: 1441815
The SQL line I typed was what the value of the srtSQL variable was when debugging. In the code, my line reads like this:

strSQL = "Select * from PHONEDB_CT WHERE [Last Name] LIKE '" & SelectUser & "*'"

When debugging (inputting in O'Malley into the program) it looks like this:

Select * From PHONEDB WHERE [Last Name] LIKE "O"MALLEY*"

Sorry, I should have made that clearer.
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Expert Comment

by:vmano
ID: 1441816
have you tried my SQL (comment) posted at Tuesday, October 27 1998 - 10:40AM PST. there is a difference between this SQL and what you are trying. please try to notice the difference carefully, and please try what i gave you and let me know.

vmano
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Author Comment

by:sehenkel
ID: 1441817
That did the trick. Thanks so much for your help!
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