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Converting a string to an array

Posted on 1998-10-29
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Last Modified: 2010-04-30
I have a string read from a text file containing data in the format of: name,status,userfolder,password
For example: Jack,active,user1,beanstalk

Now I need to convert this string to an array so I can use this data. I tried using InStr, Left$ and Right$ searching for the "," on only a string but it got too messy after a while.

The thing is that the string reads "name,status,userfolder,password" and an array will not accept the quote marks. I wonder if there is an easy way to convert it (or just lose the quotes)?
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Question by:isidor
3 Comments
 
LVL 14

Accepted Solution

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waty earned 50 total points
ID: 1442275
Use the following function :

Public Function GetTokens(sToParse As String, sToken As String) As Variant
   ' *** Returns an array to tokenized values
   ' ***  Ex:  GetTokens("Jack,active,user1,beanstalk", ",") = ({ "Jack", "active", "user1", "beanstalk" })

   Dim nTokenLen       As Integer
   Dim nTokenCnt       As Integer
   Dim nOffset         As Long
   Dim nPrevOffset     As Long
   Dim aTokens()       As String

   nTokenLen = Len(sToken)
   nOffset = InStr(sToParse, sToken)

   Do While nOffset > 0
      ReDim Preserve aTokens(nTokenCnt)
      If nOffset - nPrevOffset > 1 Then
         aTokens(nTokenCnt) = Mid$(sToParse, nPrevOffset + 1, nOffset - 1 - nPrevOffset)
      Else
         aTokens(nTokenCnt) = ""
      End If

      nPrevOffset = nOffset
      nOffset = InStr(nOffset + nTokenLen, sToParse, sToken)
      nTokenCnt = nTokenCnt + 1
   Loop

   ReDim Preserve aTokens(nTokenCnt)
   aTokens(nTokenCnt) = Mid$(sToParse, nPrevOffset + 1)
   GetTokens = CVar(aTokens)

End Function

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LVL 1

Expert Comment

by:slobstar
ID: 1442276
The following example uses the Split function to return an array from a string.
 
Dim MyArray
MyArray = Split("name,status,userfolder,password", ",")

' The "," is used as a delimiter(break-up character)
' MyArray(0) contains "name".
' MyArray(1) contains "status".
' MyArray(2) contains "userfolder".
' MyArray(3) contains "password".

I hope this is what you wanted.  /slobstar
0
 
LVL 18

Expert Comment

by:deighton
ID: 1442277
Private Sub Split(ByVal sString As String, x() As String, n As Long)

'sString your string "name,status,userfolder,password"
'x is your target array
'n is the number of elements returned


    sString = Mid(sString, 2)  'remove leading quotes
    sString = Left(sString, Len(sString) - 1) 'remove final quote
   
    If InStr(sString, ",") = 0 Then
   
        n = 1
        x(n) = sString
       
    Else
       
        While InStr(sString, ",") <> 0
       
            n = n + 1
           
            x(n) = Left(sString, InStr(sString, ",") - 1)
       
            sString = Mid(sString, InStr(sString, ",") + 1)
           
        Wend
   
        If sString <> "" Then
       
            n = n + 1
            x(n) = sString
           
        End If
       
    End If
   
   
End Sub

'sample call
Private Sub Command1_Click()

    Dim z(5) As String
    Dim n As Long

    Call Split("""name,status,userfolder,password""", z, n)
   
    For c = 1 To 5
   
        MsgBox z(c)
       
    Next
    MsgBox n

End Sub

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