Solved

Arrays of Structure

Posted on 1998-10-30
5
221 Views
Last Modified: 2010-04-02
When I assign the values to arrays of structure, how can I print them?  Or what wrong with the following my C-progam?

/* Arrays of Stuctures */
#include <stdio.h>

struct card {
      char *face;
      char *suit;
};


main()
{
      int i, j;
      struct card a[13];
      char *face[] = {"Ace", "Deuce", "Three", "Four", "Five",
                              "Six", "Seven", "Eight", "Nine", "Ten",
                              "Jack", "Queen", "King"};
      char *suit[] = {"Hearts", "Diamonds", "Clubs", "Spades"};

      for (i=0; i<=12; i++){
         printf("%6s", a[i].face);
      }
      printf("\n");
      for (j=0; j<=3; j++){
         printf("%8s", a[j].suit);
      }
      printf("\n");
      return 0;
}
0
Comment
Question by:mkido
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
5 Comments
 

Accepted Solution

by:
vmehro earned 50 total points
ID: 1176641
char *face[] = {"Ace", "Deuce", "Three", "Four", "Five",
   "Six", "Seven", "Eight", "Nine", "Ten",
   "Jack", "Queen", "King"};
????
You gotta initialize the member "face" of the structure a[]
like
a[0] = {"Ace", "Hearts"}, etc
0
 
LVL 5

Expert Comment

by:scrapdog
ID: 1176642
or you could make face and suit integers in your structure (to be used as indices)

struct card {
int face;
int suit;
}

and print it out the fields like this:

for (i=0; i<=12; i++){
   printf("%6s", face[a[i].face]);

0
 
LVL 22

Expert Comment

by:nietod
ID: 1176643
>>You gotta initialize the member "face" of the structure a[]
>>   like
>>   a[0] = {"Ace", "Hearts"}, etc

That will not compile.  The "{ }" syntax may only be used during construction.  The "a[0] ="  is after constuction.

Try

struct card a[13] = {{"Ace","Hearts"},
   {"Duece","Hearts"},
   {"Thre","Hearts"},
   {"Four","Hearts"},
   {"Five","Hearts"},
   {"Six","Hearts"},
   {"Seven","Hearts"},
   {"Eight","Hearts"},
   {"Nine","Hearts"},
   {"Ten","Hearts"},
   {"Jack","Hearts"},
   {"Queen","Hearts"},
   {"King","Hearts"}};
0
 

Author Comment

by:mkido
ID: 1176644
If I want to avoid the following long initialization, how do you do?  Thanks.
struct card a[52] = {{"Ace","Hearts"},
         {"Duece","Hearts"},
         {"Thre","Hearts"},
         {"Four","Hearts"},
         {"Five","Hearts"},
         {"Six","Hearts"},
         {"Seven","Hearts"},
         {"Eight","Hearts"},
         {"Nine","Hearts"},
         {"Ten","Hearts"},
         {"Jack","Hearts"},
         {"Queen","Hearts"},
         {"King","Hearts"}},
         {"Ace","Diamonds"},
         {"Duece","Diamonds"},
         {"Thre","Diamonds"},
         {"Four","Diamonds"},
         {"Five","Diamonds"},
         {"Six","Diamonds"},
         {"Seven","Diamonds"},
         {"Eight","Diamonds"},
         {"Nine","Diamonds"},
         {"Ten","Diamonds"},
         {"Jack","Diamonds"},
         {"Queen","Diamonds"},
         {"King","Diamonds"},
         {"Ace","Clubs"},
         {"Duece","Clubs"},
         {"Thre","Clubs"},
         {"Four","Clubs"},
         {"Five","Clubs"},
         {"Six","Clubs"},
         {"Seven","Clubs"},
         {"Eight","Clubs"},
         {"Nine","Clubs"},
         {"Ten","Clubs"},
         {"Jack","Clubs"},
         {"Queen","Clubs"},
         {"King","Clubs"}},
         {"Ace","Spades"},
         {"Duece","Spades"},
         {"Thre","Spades"},
         {"Four","Spades"},
         {"Five","Spades"},
         {"Six","Spades"},
         {"Seven","Spades"},
         {"Eight","Spades"},
         {"Nine","Spades"},
         {"Ten","Spades"},
         {"Jack","Spades"},
         {"Queen","Spades"},
         {"King","Spades"}};


0
 
LVL 22

Expert Comment

by:nietod
ID: 1176645
You could use a loop to initialize the card array from an array of suites and array of face names, like

char *Suits[4] = {"Clubs","Hearts","Spafes",Diamonds"};
char *Faces[13]  = {"Ace","Deuce","Two",Three","Four","Five","Six",
    "Seven","Eight","Nine","Ten","Jack","Queen","King"};
card a[52];

int SuitNum = 0;
int FaceNum = 0;
for (int i = 0; i < 52; ++i)
{
   a[i].suit = Suites[SuiteNum];
   a[i].face = Faces[FaceNum];
   ++FaceNum;
   if (FaceNum >= 13)
   {
     ++SuiteNum;
     FaceNum = 0;
   }
}


Note that if you use this approach, the string values in the card array point to string that are used multiple times.  These string should not be changed.  (Although the pointers can be).  To make this safe, I would declare the card structure as having "const char *" pointers not just "char *" pointers.
0

Featured Post

Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Unlike C#, C++ doesn't have native support for sealing classes (so they cannot be sub-classed). At the cost of a virtual base class pointer it is possible to implement a pseudo sealing mechanism The trick is to virtually inherit from a base class…
What is C++ STL?: STL stands for Standard Template Library and is a part of standard C++ libraries. It contains many useful data structures (containers) and algorithms, which can spare you a lot of the time. Today we will look at the STL Vector. …
The viewer will be introduced to the technique of using vectors in C++. The video will cover how to define a vector, store values in the vector and retrieve data from the values stored in the vector.
The viewer will be introduced to the member functions push_back and pop_back of the vector class. The video will teach the difference between the two as well as how to use each one along with its functionality.

733 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question