Solved

Arrays of Structure

Posted on 1998-10-30
5
218 Views
Last Modified: 2010-04-02
When I assign the values to arrays of structure, how can I print them?  Or what wrong with the following my C-progam?

/* Arrays of Stuctures */
#include <stdio.h>

struct card {
      char *face;
      char *suit;
};


main()
{
      int i, j;
      struct card a[13];
      char *face[] = {"Ace", "Deuce", "Three", "Four", "Five",
                              "Six", "Seven", "Eight", "Nine", "Ten",
                              "Jack", "Queen", "King"};
      char *suit[] = {"Hearts", "Diamonds", "Clubs", "Spades"};

      for (i=0; i<=12; i++){
         printf("%6s", a[i].face);
      }
      printf("\n");
      for (j=0; j<=3; j++){
         printf("%8s", a[j].suit);
      }
      printf("\n");
      return 0;
}
0
Comment
Question by:mkido
5 Comments
 

Accepted Solution

by:
vmehro earned 50 total points
ID: 1176641
char *face[] = {"Ace", "Deuce", "Three", "Four", "Five",
   "Six", "Seven", "Eight", "Nine", "Ten",
   "Jack", "Queen", "King"};
????
You gotta initialize the member "face" of the structure a[]
like
a[0] = {"Ace", "Hearts"}, etc
0
 
LVL 5

Expert Comment

by:scrapdog
ID: 1176642
or you could make face and suit integers in your structure (to be used as indices)

struct card {
int face;
int suit;
}

and print it out the fields like this:

for (i=0; i<=12; i++){
   printf("%6s", face[a[i].face]);

0
 
LVL 22

Expert Comment

by:nietod
ID: 1176643
>>You gotta initialize the member "face" of the structure a[]
>>   like
>>   a[0] = {"Ace", "Hearts"}, etc

That will not compile.  The "{ }" syntax may only be used during construction.  The "a[0] ="  is after constuction.

Try

struct card a[13] = {{"Ace","Hearts"},
   {"Duece","Hearts"},
   {"Thre","Hearts"},
   {"Four","Hearts"},
   {"Five","Hearts"},
   {"Six","Hearts"},
   {"Seven","Hearts"},
   {"Eight","Hearts"},
   {"Nine","Hearts"},
   {"Ten","Hearts"},
   {"Jack","Hearts"},
   {"Queen","Hearts"},
   {"King","Hearts"}};
0
 

Author Comment

by:mkido
ID: 1176644
If I want to avoid the following long initialization, how do you do?  Thanks.
struct card a[52] = {{"Ace","Hearts"},
         {"Duece","Hearts"},
         {"Thre","Hearts"},
         {"Four","Hearts"},
         {"Five","Hearts"},
         {"Six","Hearts"},
         {"Seven","Hearts"},
         {"Eight","Hearts"},
         {"Nine","Hearts"},
         {"Ten","Hearts"},
         {"Jack","Hearts"},
         {"Queen","Hearts"},
         {"King","Hearts"}},
         {"Ace","Diamonds"},
         {"Duece","Diamonds"},
         {"Thre","Diamonds"},
         {"Four","Diamonds"},
         {"Five","Diamonds"},
         {"Six","Diamonds"},
         {"Seven","Diamonds"},
         {"Eight","Diamonds"},
         {"Nine","Diamonds"},
         {"Ten","Diamonds"},
         {"Jack","Diamonds"},
         {"Queen","Diamonds"},
         {"King","Diamonds"},
         {"Ace","Clubs"},
         {"Duece","Clubs"},
         {"Thre","Clubs"},
         {"Four","Clubs"},
         {"Five","Clubs"},
         {"Six","Clubs"},
         {"Seven","Clubs"},
         {"Eight","Clubs"},
         {"Nine","Clubs"},
         {"Ten","Clubs"},
         {"Jack","Clubs"},
         {"Queen","Clubs"},
         {"King","Clubs"}},
         {"Ace","Spades"},
         {"Duece","Spades"},
         {"Thre","Spades"},
         {"Four","Spades"},
         {"Five","Spades"},
         {"Six","Spades"},
         {"Seven","Spades"},
         {"Eight","Spades"},
         {"Nine","Spades"},
         {"Ten","Spades"},
         {"Jack","Spades"},
         {"Queen","Spades"},
         {"King","Spades"}};


0
 
LVL 22

Expert Comment

by:nietod
ID: 1176645
You could use a loop to initialize the card array from an array of suites and array of face names, like

char *Suits[4] = {"Clubs","Hearts","Spafes",Diamonds"};
char *Faces[13]  = {"Ace","Deuce","Two",Three","Four","Five","Six",
    "Seven","Eight","Nine","Ten","Jack","Queen","King"};
card a[52];

int SuitNum = 0;
int FaceNum = 0;
for (int i = 0; i < 52; ++i)
{
   a[i].suit = Suites[SuiteNum];
   a[i].face = Faces[FaceNum];
   ++FaceNum;
   if (FaceNum >= 13)
   {
     ++SuiteNum;
     FaceNum = 0;
   }
}


Note that if you use this approach, the string values in the card array point to string that are used multiple times.  These string should not be changed.  (Although the pointers can be).  To make this safe, I would declare the card structure as having "const char *" pointers not just "char *" pointers.
0

Featured Post

Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
maze travler 6 51
Need some help with listview limit text 20 98
object modeling - load and save functions 5 60
how to convert c++ code to Android App 3 83
Unlike C#, C++ doesn't have native support for sealing classes (so they cannot be sub-classed). At the cost of a virtual base class pointer it is possible to implement a pseudo sealing mechanism The trick is to virtually inherit from a base class…
What is C++ STL?: STL stands for Standard Template Library and is a part of standard C++ libraries. It contains many useful data structures (containers) and algorithms, which can spare you a lot of the time. Today we will look at the STL Vector. …
The goal of the video will be to teach the user the concept of local variables and scope. An example of a locally defined variable will be given as well as an explanation of what scope is in C++. The local variable and concept of scope will be relat…
The viewer will learn additional member functions of the vector class. Specifically, the capacity and swap member functions will be introduced.

867 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

21 Experts available now in Live!

Get 1:1 Help Now