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HDC TO BITMAP , thanks

With Visual C++, I want to copy client area output from HDC to Bitmap, how to ?
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zqian103198
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zqian103198
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nietodCommented:
I'm not sure exactlyu what you mean.  

You can copy the client area to a bitmap using BitBlt() (or similar function).  But this copies the client area as displayed on the screen.  This if a window is partly covering the window you are copying, you will see the covering window.

If by "output", you mean you want to copy the client area as if there are no windows covering it to the bitmap.  That is harder.  The mess WM_PRINTCLIENT can be used for this.  But not all windows will handle this message properly, but most will.

Try to explain which approach you want, and then I will provide more details, if necessary.
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zqian103198Author Commented:
I did lot's of drawings in the client area of a SDI program, what I am going to do is to save them to a bitmap file.

BitBlt will transfer data from DC into DC. I want to find a way to transfer data from DC to Bitmap.
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nietodCommented:
Actually BitBlt transfers a bitmap's data from DC to DC.  That is what you want.  (Maybe).  To do this You would

Believe it or not, the following 10 steps are what you use to transfer images from one DC to another.  You would think there is an easier way.  There is not.

1.  Get the client area DC using GetDC();
2. Create a memory DC (a DC that draws to a memory bitmap as opposed to a hardware bitmap) using GetCompatibleDC() and the client area DC.
3.  Create a memory bitmap compatible with the client area DC (and memory DC, but use the client area one) using CreateCompatibleBitMap().
4.  Select the bitmap into the memory DC with SelectObject() and save the old bitmap handle that is returned.
5.  BitBlt() the image from the client DC to the memory DC.
6.  Select the old bitmap handle back into the memory DC with SelectObject().  
7.  Delete the memory DC with DeleteDC().
8.  Release the client area DC using ReleaseDC().
9.  Use your memory bitmap as you see fit.
10.  Delete the bitmap with DeleteObject().
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nietodCommented:
Now that is what you asked for.  That probably isn't what you need (exactly).  If for example, this is a drawing program, What would you do when the image gets covered up by another window and then the window is moved so you need to redraw what was behind it?  You can't, right?  

The usuall way to handle this is to do the opposite of what you are trying to do.  Rather than drawing the image on the screen and later getting a copy into a memory bitmap.  They draw the  image in a memory bitmap and then BitBlt() this to the screen to show changes.  then if the screen is covered and uncovered, they still have a copy of the image to put up on the screen.

make sense?
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zqian103198Author Commented:
The answer above is clear and useful.
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