Rounding integer value

Try this method:
private int round( double num )
{
      if ( num >= 10 ) {
            return round( (double)num / 10 ) * 10;
      }
      return (int)Math.round(num);
}
Hope this helps.

hey omok.
your code gave me number 689 when I called it with 689 not 700.

private int round( double num )
   {
   if ( num >= 10 ) {
   return round( (double)num / 10 ) * 10;
   }
   return (int)Math.round(num);
}

Comment.
Thank' s for answers.
Actually that code was usuful for my purpose.

if ((maxnumber>=100) && (maxnumber<1000))
          {
            maxnumber = (int)(maxnumber/100)*100;
          }
if ((maxnumber>=10) && (maxnumber<100))
          {
            maxnumber = (int)(maxnumber/10)  * 10;
          }

tittapo,
Are you sure my method doesn't work?
I have written a test program and tested it before I posted it here???
I am using JDK1.1.7 on NT4

tittapo,
I don't think your code will work as (maxnumber/10) will always round down because you are doing Integer division.
Try 49, it will give you 40 instead of 50.

public static int round (int i)
{
  if (i >= 100)
  {
    int mod = i % 100;
    return (mod >= 50)?(i + (100 - mod)):( i - mod);
  }
  else
  {
    int mod = i % 10;
    return (mod >= 5)?(i + (10 - mod)):( i - mod);
  }
}


2-nd attempt.

Cheers.