Is it possible for a java window to be forced to remain the topmost window?
For my purposes this app will always only run under Win95/98/NT so a native method approach is acceptable, and will work. However, to do it that way I need a guaranteed way of getting the HWND for the window which I have not yet found. Calling GetForegroundWindow won't do since there is no way to guarantee that the window is the foreground window when the call is made.
Regarding your second question - the best way I found to find the window was to assign a unique name for each window (in the title), and the in the native method go throuh all the windows until you find the one with the expected name. However, I hope this code will do the trick for you. If you need more explenation, ask.
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import java.awt.*;
public class alwaysOnTop {
/**
* Constructor.
*/
public alwaysOnTop () {
}
public static void main(String args[]) {
myframe mf1 = new myframe();
myframe mf2 = new myframe();
myframe mf3 = new myframe();
myframe mf4 = new myframe();
ontopframe tf = new ontopframe();
mf1.add(new Label("b1"));
mf1.show();
mf2.add(new Label("b2"));
mf2.show();
mf3.add(new Label("b3"));
mf3.show();
mf4.add(new Label("b4"));
mf4.show();
tf.add(new Label("Alway on top"));
tf.show();
}
}
class myframe extends Frame {
public myframe() {
setLayout( new FlowLayout());
}
public Dimension minumumSize() {
return new Dimension( 200, 200 );
}
public Dimension preferredSize() {
return new Dimension( 200, 200 );
}
public Dimension getPreferredSize() {
return preferredSize();
}
}
class ontopframe extends Frame implements Runnable {
public final static int TO_TOP_TIME = 100; // Max time to top in milliseconds.
Thread top_thread;
boolean stop = false;
public ontopframe() {
setLayout( new FlowLayout());
top_thread = new Thread(this);
top_thread.start();
}
public Dimension minumumSize() {
return new Dimension( 200, 200 );
}
public Dimension preferredSize() {
return new Dimension( 200, 200 );
}
public Dimension getPreferredSize() {
return preferredSize();
}
public void run() {
while(!stop) {
toFront();
try{
top_thread.sleep(TO_TOP_TI
} catch ( Exception e ){}
}
}
}