Solved

Convert file

Posted on 1998-11-10
6
217 Views
Last Modified: 2010-04-15
hai..

can we convert the file which contains hex / character / base64 format into text format that can be read. Assume that i have this line of hex formated:

00 02 FF 0F 47 5F

after convert i got this text "Hello". Can we do that?

Thanks,

Suhaimi
0
Comment
Question by:suhai
  • 2
  • 2
  • 2
6 Comments
 
LVL 84

Expert Comment

by:ozo
ID: 1254131
Are you sure that
00 02 FF 0F 47 5F
converts into "Hello"?  How did you convert it?
what format is this supposed to be?  hex, or character, or base64?
0
 
LVL 1

Expert Comment

by:Grailman
ID: 1254132
"can we convert the file ... into text format that can be read"
I don't understand since this is how we read text files. Opening a file with the binary values 48 45 4C 4C 4F will give the text "HELLO". Do you mean you want to open a text file with the text "48 45 4C 4C 4F" and have it convert the three chars "48 " into one char "H"?

0
 

Author Comment

by:suhai
ID: 1254133
Yes grailman,  you've got my point. Do you have any program converter or some sample program?
0
PRTG Network Monitor: Intuitive Network Monitoring

Network Monitoring is essential to ensure that computer systems and network devices are running. Use PRTG to monitor LANs, servers, websites, applications and devices, bandwidth, virtual environments, remote systems, IoT, and many more. PRTG is easy to set up & use.

 
LVL 84

Expert Comment

by:ozo
ID: 1254134
while( scanf("%2x",&c)>0 ){ putchar(c); }
0
 
LVL 1

Accepted Solution

by:
Grailman earned 10 total points
ID: 1254135
void Convert(char* pStr, int StrSize)
{
  // pStr is a pointer to text string to be converted
  // and should be checked before calling this to
  // make sure all chars are '0-9' 'a-f' A-F' space <CR> or <LF>

  char ch;
  char Byte;
  int NibbleCount = 0;

  for(int i = 0; i < StrSize; i++)
  {
    ch = pStr;

    // make sure we have a char
    if(ch != 0x0A && ch != 0x0D && ch != 0x20)
    {
      if            (ch >= '0' && ch <= '9')      ch -= '0';
      else if      (ch >= 'a' && ch <= 'f')      ch -= ('a' - 10);
      else if      (ch >= 'A' && ch <= 'F')      ch -= ('A' - 10);

      if(!(NibbleCount % 2))                  // Set lower nibble
      {
        Byte = (ch << 4);
      }
      else                                          // Set upper nibble
      {
        Byte += ch;
        printf("%c", Byte);
      }
      NibbleCount++;                        // increment for each nibble
    }
    else
      printf("%c",ch);                        // print <CR><LF> or Space

    pStr++;
  }
}

0
 

Author Comment

by:suhai
ID: 1254136
Thanks.
0

Featured Post

Problems using Powershell and Active Directory?

Managing Active Directory does not always have to be complicated.  If you are spending more time trying instead of doing, then it's time to look at something else. For nearly 20 years, AD admins around the world have used one tool for day-to-day AD management: Hyena. Discover why

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Summary: This tutorial covers some basics of pointer, pointer arithmetic and function pointer. What is a pointer: A pointer is a variable which holds an address. This address might be address of another variable/address of devices/address of fu…
Windows programmers of the C/C++ variety, how many of you realise that since Window 9x Microsoft has been lying to you about what constitutes Unicode (http://en.wikipedia.org/wiki/Unicode)? They will have you believe that Unicode requires you to use…
The goal of this video is to provide viewers with basic examples to understand how to use strings and some functions related to them in the C programming language.
Video by: Grant
The goal of this video is to provide viewers with basic examples to understand and use for-loops in the C programming language.

863 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

25 Experts available now in Live!

Get 1:1 Help Now