Solved

# Convert file

Posted on 1998-11-10
214 Views
hai..

can we convert the file which contains hex / character / base64 format into text format that can be read. Assume that i have this line of hex formated:

00 02 FF 0F 47 5F

after convert i got this text "Hello". Can we do that?

Thanks,

Suhaimi
0
Question by:suhai
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LVL 84

Expert Comment

Are you sure that
00 02 FF 0F 47 5F
converts into "Hello"?  How did you convert it?
what format is this supposed to be?  hex, or character, or base64?
0

LVL 1

Expert Comment

"can we convert the file ... into text format that can be read"
I don't understand since this is how we read text files. Opening a file with the binary values 48 45 4C 4C 4F will give the text "HELLO". Do you mean you want to open a text file with the text "48 45 4C 4C 4F" and have it convert the three chars "48 " into one char "H"?

0

Author Comment

Yes grailman,  you've got my point. Do you have any program converter or some sample program?
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LVL 84

Expert Comment

while( scanf("%2x",&c)>0 ){ putchar(c); }
0

LVL 1

Accepted Solution

Grailman earned 10 total points
void Convert(char* pStr, int StrSize)
{
// pStr is a pointer to text string to be converted
// and should be checked before calling this to
// make sure all chars are '0-9' 'a-f' A-F' space <CR> or <LF>

char ch;
char Byte;
int NibbleCount = 0;

for(int i = 0; i < StrSize; i++)
{
ch = pStr;

// make sure we have a char
if(ch != 0x0A && ch != 0x0D && ch != 0x20)
{
if            (ch >= '0' && ch <= '9')      ch -= '0';
else if      (ch >= 'a' && ch <= 'f')      ch -= ('a' - 10);
else if      (ch >= 'A' && ch <= 'F')      ch -= ('A' - 10);

if(!(NibbleCount % 2))                  // Set lower nibble
{
Byte = (ch << 4);
}
else                                          // Set upper nibble
{
Byte += ch;
printf("%c", Byte);
}
NibbleCount++;                        // increment for each nibble
}
else
printf("%c",ch);                        // print <CR><LF> or Space

pStr++;
}
}

0

Author Comment

Thanks.
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