Passing Null-parameters to User functions

If I pass parameters with a null value to my own build userfunction, the function is not started at all. This means that a check for null value must happen before entering the function. Is this a standard behavior of MS-Access, and if yes, can I prevent this, so that I can do the check within the function itself.

Thanks and regards,
Rene
nlnfmrvrAsked:
Who is Participating?
 
JeroenWCommented:
Dear nlnfmrvr,

You try to pass Null-values to input-arguments that do not accept Null-values. Access is not a very strong-typed tool, but you can't get away with everything.

Whenever you want to pass Null-values, be shure to declare the variable in the function-declaration as a Variant,
like:
Function StrTran(cFindIn As Variant, cFind As Variant, cRep As String, nReplaces As Integer) As String

Greetings,

Jeroen Westera
0
 
peroveCommented:
Use the optional argument when declaring the function, the do the test within the function. See help on optional for details, be sure to put the optional parameters in the end
ex:
function Bullshit(a as integer, optional b as variant)
if insnull(b) then
   msgbox "B is null and perove is a nice person)
end if
end  function

sub TestBullShit
dim b as variant
a = 2
s= bullshit(a,b)
end sub

let me know

perove

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nlnfmrvrAuthor Commented:
Sorry Perove, but it doesn't work.

This is my function :

Function StrTran(cFindIn As String, cFind As String, cRep As String, nReplaces As Integer) As String
'
'Search and replace characters within a string
'
    Dim loop1 As Boolean, cResult As String, x As Integer, nPos As Integer
       
    If Not IsNull(cFindIn) And Not IsNull(cFind) Then
        loop1 = True
        Do While loop1
            nPos = InStr(1, cFindIn, cFind)
            If nPos = 0 Then
                loop1 = False
            Else
                cFindIn = Left(cFindIn, nPos - 1) + cRep + Mid(cFindIn, nPos + Len(cFind))
                x = x + 1
                loop1 = IIf(x = nReplaces And nReplaces <> 0, False, loop1)
            End If
        Loop
     End If
    StrTran = cFindIn
End Function

Even when I swap the parameters and assure that the first one is always a valid value (being not null), the result is still #error.

Any other idea.
Cheers,
Rene
0
 
nlnfmrvrAuthor Commented:
To Jeroen,

As stated above, excellent because it works.
Thanks

Rene de Vriend

0
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