maybe i am missing something, but if
the explicit formula should be:
C(n)=log(2)[n+1]-1
than the recurrence relation should be
C(n+1)=C(n) + log(2)[n+1]
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I don't think it matters. The definition for the height of a
tree is: the number of nodes on the longest path from the root
to a leaf. So, worst case binary tree would be one that has nodes attatched to the left or right side only (a diagonal).
maybe i am missing something, but if
the explicit formula should be:
C(n)=log(2)[n+1]-1
than the recurrence relation should be
C(n+1)=C(n) + log(2)[n+1]
I had math student help me. With each call to the algorithm the list of N elements is halved. Since the algorithm recursively calls itself twice the formula is:
C(N) = 2*C(N/2)
To Prove relation:
Let N = 2^n
sorry took so long to respond. e-mail and internet down.
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