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weird error in gcc

Posted on 1998-11-12
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Last Modified: 2010-04-15
I compiled the codes below with gcc 2.7.2.3-8

#include <stdio.h>

int main(int argc, char *argv[]) {
 printf ("test");
 int i;  
 for (i = 0; i < 5; i++)
  printf ("%d", i);
 return 0;
}

The error I got:
  In function `main`:
line 6: parse error before int
line 7: i undeclared (first use this function)

HOWEVER, if I move 'int i;' before printf function, I didn't get the error. I never learn ANSI C, does ANSI C say that variable declaration should be done before calling printf function? Also, if I write 'for (int i = 0; ;) I will get errors. So, in C we can't put 'int' inside the for()?

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Question by:screwdriver
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Accepted Solution

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rbr earned 20 total points
ID: 1254240
change the 2 lines printf and int

int i;
printf ("test");

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Expert Comment

by:rbr
ID: 1254241
You can't use a declaration only after a {
e.g. you can write

int (i=0;i<100;i++) {
      int j=i;
      printf ("%d",j);
}

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Expert Comment

by:rbr
ID: 1254242
Sorry not int (i=0;i<100;i++)
for (i=0;i<100;i++)
a for opens a new block so new local declarations are allowed. There for you can write for (int i...).
It's the same for while, if, switch, ..
You can also write
int main(int argc, char *argv[]) {
     printf ("test");
       {
       int i;   
       for (i = 0; i < 5; i++)
          printf ("%d", i);
       return 0;
     }
}
0
 
LVL 10

Expert Comment

by:rbr
ID: 1254243
Sorry another error. There for you can write for (int i...). (Wrong sentence)
So you can't write for (int i...) Local declarations are only allowed after {.
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Author Comment

by:screwdriver
ID: 1254244
I prefer to hear explanation about ANSI C rule. I have already figured out that I should move int before printf to get rid off the error.
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