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USING WC and GREP together

Posted on 1998-11-15
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Last Modified: 2013-12-26
I need to use the "GREP" and "WC" commands on a single line to find out how many accounts are in the same group   /etc/passwd (My own server)...what is the proper syntax to use?
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Question by:EaglesFan
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by:ozo
ID: 1294156
grep "^[^:]*:[^:]*:[^:]*:$group:" /etc/passwd | wc
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by:gothick
ID: 1294157
You can use the "cut" command as an alternative to that grep syntax -- it can cut out
the group column more easily, then you can pass that to grep/wc.
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by:bchew
ID: 1294158
cut -d: -f3 /etc/passwd | grep <group number> | wc -l
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by:n0thing
ID: 1294159
awk -F: '{print $4}' /etc/passwd | grep <groupid> | wc -l
is another solution
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by:ozo
ID: 1294160
#the above solutions with cut and awk probably want to use grep -x
#or, using neither grep nor wc:
perl -F: -ane '$c+=$F[3]=='«groupid»';END{print "$c\n"}' /etc/passwd
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by:bchew
ID: 1294161
ozo is right about grep -x.  Otherwise, you will be counting groups you didn't intend.  For instance, if you grep for 100 without the -x you would also get groups 1000, 1100, 2100, etc.

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kellyjj earned 50 total points
ID: 1294162
grep "<group id>" /etc/passwd |wc -l
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by:bchew
ID: 1294163
kellyjj

First of all, your "answer" won't work (it will give lots of false hits)!  Furthermore, what you propose is as an has already presented by others as comments!  I believe this is a blatant attempt to "steal" unearned points rather than try to help someone with a solution to their problem.
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by:braveheart
ID: 1294164
I reckon you should use nawk:

nawk -F: '{groups[$4]++}\\
END      {for (grp in groups) print grp, groups[grp]}' \
/etc/passwd

This will list two columns - the first contains the number of occurences of the group and the second contains the group id.
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by:braveheart
ID: 1294165
Take it easy.
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